LI b R.AFIY OF THE UNIVERSITY Of ILLINOIS 510.84 I^6r' no. 140-147 copo2 CENTRAL CIRCULATION BOOKSTACKS The person charging this material is re- sponsible for its renewal or its return to the library from which it was borrowed on or before the Latest Date stamped below. You may be charged a minimum fee of $75.00 for each lost book. Theft, mutilation, and underlining of books are reasons for disciplinary action and may result In dismissal from the University. TO RENEW CALL TELEPHONE CENTER, 333-8400 UNIVERSITY OF ILLINOIS LIBRARY AT URBANA-CHAMPAIGN OCT 5 NOV 2 139 When renewing by phone, write new due date below previous due date. L162 Digitized by the Internet Archive in 2013 http://archive.org/details/cabledrivertermi146yama 0.84- -^^^ DIGITAL COMPUTER LABORATORY o UNIVERSITY OF ILLINOIS OP- ^ URBANA^ ILLINOIS REPORT NO. Ik6 CABLE DRIVER AND TERMINATOR DESIGN Shlgeharu Yamada I August 21, 1963 This work was supported in part by Atomic Energy Commission Contract AT(11-1)-1018 T-U, b ,^ ^ ^ P • -^ 1 = INTRODUCT ION This paper gives a theoretical treatment of a cable driver and cable teiTuinator design of very general applicability. In general^ problems of cable driver and terminator design separate into two parts: (1) the noise problem^, which includes both inter-channel crosstalk and the ground noise problem of coupling between different machines at different ground references; (2) performance of the driver and terminator network^ subject to prescribed level shifting^ to give sufficient termina- tion--including an allowable limit for reflection under the worst-case operation. The first problem^ ground noise^ sometimes becomes considerable in magnitude;, especially if a high-level system and a low-level system are connected „ Obviously in AC systems ground noise can be suppressed by using a transfonner to separate the longitudinal circuit coupling the two systems. In a DC system^ a linear differential amplifier or a balanced transmission line can efficiently reject ground noise. On the other hand^ from standpoint of economy a differential amplifier terminator is not preferable if ground noise can be held within allow- able limits. The second problem mentioned above can be summarized as the matching and level shifting problem. Cable impedance matching is not necessarily complete because of the nonlinear amplification of the terminator. (This situation will be discussed later.) A linear emitter follower driver and terminator are con- sidered to give a better m.atch at the sending and receiving ends^ but level shifting is rather poor. From the above circumstances^ a driver and a terminator which give reasonable matching and complete level shifting are preferable in most digital applications. Such designs impose no additional level shifting circuitry at the stage preceding the driver and the stage succeeding the terminator. Accordingly^ the driver and terminator can be connected directly to logic circuits without these intermediate stages. These considerations suggest a suitably designed on-off driver and on-off terminator. Table 1 shows possible combinations of an on-off driver and -1- Driver Terminator \ — O (a) A/ — o '+v. 1 \ / (a) -> (a' ) ^ , , 0/ \-v r v-^2' (a) -> (b-) (b) -> (c') \ / +V^ ■V / V ''+VA / (b) - (d') .-v^y V / V (d') Table lo Possible Combinations of Cable Driver and Terminator an on-off terminator which give both noninverted information transmission and arbitrary level shift. These combinations work as a regenerative OR circuit and AND circuit in cooperation with the terminator. Consider allowable limitation of the reflection for the driver- terminator pair. The limits on the reflected wave depends upon the delay time of the reflected wave from the main signal and upon the turn-on time of the terminator transistor. When the reflected wave comes after the completion of turn-on^ the limits on the reflected wave will be less severe: once the tran- sistor comes to a stable state^ the reflected wave does not change the operating state unless min S(t) - |R(t) + N(t)| > critical signal (l.l) Here^ critical signal means that signal level which breaks the saturated operation. Signal min S(t) means that signal level which satisfies the lower- most operating condition. If a represents the ratio of the critical signal to the minimum signal^, then the above equation gives ^ . JjKtWMt)! ^ „ (1.2) mm S(tj ^ Therefore, if a is designed to be 1/2, this gives |R(t) + N(t)| < 1/2 min S(t) = l/k ts{t) (I.3) For the most part, min S(t) is close to the 1/2 of the signal level difference of the two stable states. On the other hand, if the reflected wave arrives before the completion of switching, the allowable limitation on the maximum reflected wave becomes more severe. When the switching speed of the terminator is less than 2i/v (where V is the group velocity in the cable and & is the length of the cable), the condition max |5S(t)| > |R(t) + N(t)| (l.^) must be satisfied. Here max |&S(t)| is the allowable signal level variation which guarantees worst-case operation. This case is much more severe than the former case^ but if the switching delay caused by reflection is allowed to a certain extent^ the limitation of the reflection constraint is relaxed o The operational equation which defines this delay is 1 - e"^ = (1 - e"^)F(p), where 1 R '^^'^ Here R is the ratio of the reflected wave to the signal and T is the relative build- up time (or fall time) without the presence of the reflected wave. T is the cable delay. The delay depends both upon the reflected level and the cable delay time. Figure 1 shows the relative build-up delay caused by the reflection as calculated from Eq, (1.5 ) = •H -P ft pi I H •H 2.0 o •H -P O D H Ch (D -P o -p •H oj 1.8 •H -p ^ 1.6 H •H f^ 1.1+ 1.2 1.0 k q/ / / / / ^ y /. ^ X ^ (1) Reflected wave delay is 0.5 T \2J Reflected wave delay is 0.8 T 0.1 0.2 0.3 0.4 0.5 R Figure 1. Ratio of Reflected Wave to Signal (r) 2c EQUATIONS AT EQUILIBRIUM Consider the circuit shown in Fig. 2. This circuit can be expressed by the following equation (especially convenient for noise estimation): C) = [A][V] + [B](p (2.1) (p-iBH-^) Figure 2 » (v) does not depend upon the termination condition. [A] and [b] depend upon the circuit configuration o If the network is divided into cascaded subcircuits^ each has an [A.]^ [B.] respectively. [A] and [b] can be expressed^ as in the ordinary chain matrix, by the matrix of a subcircuit as follows : [A] = ... [A^^] + [B2][A2] + [B^][B2][A^; [b] = ... [b^JLb^JIb^] (2.2) Equation (2.l) should be solved for given input/output voltages and current conditions (these are given by the speed requirements of the regenerating transistor) and for given condition of input impedance, say, -6- Z . - R^ ; m 0' ^. = QRn (2.3) m \ ~j / for one of two equilibrium conditions „ Network N is a passive linear circuit; therefore^ the solution of Eq. (2.1) under the condition of Eq. (2.3) a-nd given voltage and current conditions^ must be positive. Figure 3 shows a simplified structure. In this case the input circuit gives only the termination condition and there are no energy sources in the input circuit except for noise and the reflected wave. The input terminating condition gives the change in the output voltage and current. This structure is suitable for a cable drivers--terminator pair^ because the cable terminator need not serve as an energy source for the driver; it sometimes causes trouble with the preceding stage of the driver. Figure k is the simplest circuit topology of the form of Fig. 3 and also is a necessary and sufficient circuit for a level-shifting terminator. (.) can be eliminated from Eq. (2.l) in this case: Q) = [A](V) . [Z] (y (2.U) Here [Z] is the output impedance matrix which corresponds to the input condition. The problem is to find the network from Eq. (2.l) or Eq. (2,^) subject to the condition of Eq. (2.3). For the circuit of Fig. h^ the steady-state equation for the two input/ output states, as indicated in Eq. (2.^);, is :;) ■ G:; S) © • C" -l) (':) --- Here (e ;, j ) corresponds to the input switch open; {e , j^) corresponds to the input switch closed. % Figure 3 Figure h 11 Rq + R^ + Rg R^Rg 21 R2(Rq + R^) + R^(Rq + R-j_) + RqR^ A ^o"\ 12 Rq + R^ + Rg 22 R2(Rq + R^) + R^(Rq + R^) + R^R^ \i Ro -^ Ri - \ ^ \^\^\ + R^) ^ RqR'] ■'22 r^CRq + Rq) + RqCRq + R^) + RqRi The impedance condition for shorted T gives ^0^0 R. ^ ^0' (2.7) The se equations determine R^ R^ R for the given (e^ j )^ (e^ j ) and V^ V , Generally, to get the value of R , R , R , we must solve a set of higher order equations. When we limit the input impedance variation AZ. , one of V., or V^ m ' 1 2 cannot he given arbitrarily and the equation to he solved becomes of ths sixth order. For simplicity, in our case we omit the input impedance variation con- dition; therefore, V and V can be given arbitrarily within the limitation of the passive network approximation, and the equation reduces to a third order equation--or even a second order equation. Equation (2.8) gives R and R as the function of R , e , e , j , j , V^ and V^; ^0 = ';-^o-^iQ 1 + (e^ - e^) - R2(j^ + jg)" V. \ ^ Jl^2 1 V^ - e, + j R^ " 2 1 '1 2 (2.8) These two equations and Eq. (2.7) give an equation for R , If another impedance relation, which specifies the impedance condition where T is open, is added, the equation for R becomes much more complicated. From Eq. (2,7) we get 10 AX + AX + A = (2.9) Another added impedance relation R„(R, + Rp) R ,-^0 «0*\ 2 Q > 1 gives a similar equation: BqX + B^X + B^ = (2.10) where X = Vg - e_|_ + j^Rg, Ao = Aq(R2) Bo(R^) ^1 " ^1^^2^ B^(R2) Ag = A2(R2) B^ = B2(R2) Equation (2.9) and Eq. (2.10) must have a common root; therefore^ the condition (necessary and sufficient) is described by: A, =0 *0 ^1 =0 *1 \ =1 ^s \ = (2.11) This gives a sixth order equation for R„. By solving Eq. (2.11) and substituting the root into X^ V can be determined. But this procedure is rather laborious; therefore we employ a 11 practical method which checks the input impedance variation only after getting a trial result^ and if For example^ if we put a trial result^ and if not satisfactory, revise the value of V and recalculate V, = -6 volts e = -O.5 volts j = 0.1 ma V = +6 volts e = +0.7 volts j = 1 ma then the equation for R becomes r| + 63.78 Rg - 77.98 Rg + 22.35 = (2.12) This equation involves a trivial root; therefore, after factorization this "becomes a second order equation, and gives the roots R^ = 0.7^13 (KH) R-L = O.i+995 (Kfi) Rq = 0.1207 (Kn) (2.13) These values show about 20 percent impedance variation. However, if we put V = +12 volts, and the other conditions held to the same values as before, we get Rg - 2.676 (Kfi) R = 1.05^ (Kn) Rq = 0.09907 (Kfi) (2.14) In the latter case [i^l is less than six percent for the extreme case; this will be satisfactory. So far, only mathematically accurate elements have been considered. In practice every element has tolerance variations. Consider now any circuit with all components having small variations but such that the behavior of the UNIVERSITY OF ILLINni.<; I iDDAnu 12 circuit can still t>e described completely by the analysis above. The worst case of the circuit behavior can then be described completely by an analytic method. On the other hand^ if the circuit equation itself can be described only by statistical methods, even in a macroscopic view, we cannot describe the worst-case behavior by an analytic method. Another design philosophy of net- works will be most economical: essentially a statistical design of circuits. Worst-case design sometimes gives uneconomical results. But such discussions are beyond the confines of this report. Therefore we will describe here only the determination of the worst-case equation. Assume, for convenience, that each element has small finite variations. Cross-terms of the variations can then be neglected when estimating the incremental change. A worst-case equation corresponding to Eq. (2.5) becomes 5) = l^lie)HV(i,,)] - t^(ii5)V3 (^-^5) Here [A/ s], [V/ -pn]^ and [Z/ n] represent matrices, the elements of which are multiplies by (l + e), (l - £), etc. The signs of e, 6^ T are determined by the sign of the partial derivative, -v^ is always positive. Therefore, to determine the appropriate sign of a variation, it is sufficient to check the sign of the partial derivative of e. Equation (2.5) and Eq. (2.6) give de de ^e ^e 5Ar>°' 3v->°^ 5F>°^ 5r^>° 1 2 1 ^e ^e 5F T the equivalent source voltage V_(t) increases successively^ and Z_(t) decreases. These changes add together. The circuit design in the preceding section satisfies 5^0 for the first approximation. Therefore^ the voltage change at the input of the terminator is equal to •5Z, 6Z, V^ + 6V, V. 2Rq "0 2Rq This change shows the increase of voltage for a given magnitude of impedance variation. 18 By the same method as ahove^ e (t)^ which corresponds to the switch suddenly opened, can be calculated. In this case, instead of inserting a voltage source, we insert a current source: Vo(t) ° - I(t) ^o-^^o at the place of switch. Therefore, e (t) becomes 1 , Mi) 1 +^ Vo(t - T) - Rq V^Ct - T) - Rq ^-PT e^(t) = VQ(t - T) - — - — R(i) + — 2 . , R(i) Z7wir7r~7^] - 2Rq - 2r/ - 2Rq ^ ^ (3.^) for t < T + T V^(t) is again the staircase function for t > T + T and is also determined by the resistance characteristics of the transistor and e . For t > T, by the same observation as before, e (t) decreases to the equilibrium voltage. These results are shown in Fig. 6. Equation (2.3) represents multiple reflections; the first reflected wave, delayed by 2T from the main signal, is ,Mi)v(t).iiil^!°^ - 2Rq ^0^^^ - 2Rq dt In both cases, if the imaginary part of I (which is essentially wiring inductance or parasitic capacitance) is small, the wave form distortion depends mainly upon the characteristics of the terminating transistor. The above analysis shows the equilibrium, level is higher in absolute magnitude both in the switch-on and switch-off cases; it is better to take into account these situations for a worst-case design. 19 r © Driver on Driver off (T) Be^ caused by bV^it) (2) 6e caused by gZ^ © ©-© (k) Beg caused by bV^ + bZq Figure 6. Dependence of e„(t) on Variations of V^^ and Z_ h, NOISE PROBLEMS Noise problems which arise when two computers are connected are sometimes very complicated o Noise is composed of two parts « One part is noise from adjacent channels through direct coupling between wires; the other part is noise from the ground circuit. The noise ratio of the former can be expressed by ,/|^..„,,^) ^ dx + Z n^ £ (^^^^n(x)R^e" 2JCUX _ jud V V dx (^^1) The first term represents the direct noise to the receiAz-ing end^ and the second term represents the reflected noise at the sending end. Ordinary Zmn's; Ymn's are reactancesj^ therefore^ the wave form of the noise has a pulse shape. This can be easily shown by the Laplace transformation of Eq. (^.l). The second term of Eq. (^.l) shows the distributed pulse train along the time axis, which length corresponds to the pass length of the noise. For coaxial cable, Zmn, Ymn are small. This can be checked by experiment. The second noise contribution arises from the mechanism shown in Fig. 7- When we use a transformer, longitudinal pass can be shut off; of if we use a balanced system it can be eliminated. Otherwise this kind of noise cannot be eliminated. side pass longitudinal pass hypothetical ground potential Figure 7 Estimation of the noise is as follows. Let V , V , I , I be the potential differences and the currents referred to the hypothetical ground potential. Translate these potential differences and currents by matrix [S], -20- 21 [S] = 1 2 1 2 where now [e] = [S] • [V] [1] = [S] . [I] (^.2) The equation of the transmission line is (1,) cosh [r]-^ w~^ sinh [r]^ w sinh [r]^"" cosh [r]i The matrix [r] may he considered diagonal^ hut w is not a diagonal matrix, [V] = [Z] • [I] [z]^ = [z] [z] = S[Z]S" Wq = [r]"^ • [z] w = hi ^ ^22 7 A 1_ 2 " 12^ 7^ h ^hl ' ^22^ 7^ ^22^ 7 22 1 + Z 12/ 7 (^A) Therefore^ if Z = ^oo-? "'^■'^^ longitudinal pass and the side pass are independent of each other^ and of course no noise occurs. But for an unbalanced cahle this cannot be satisfied^ while, in the balanced cable Z is equal to Z . Therefore in this latter case there exists very little longitudinal noise. Equation (^.2) also illustrates this situation when V = -V (i.e.,, balanced transmission); there exists no longitudinal crosstalk. In any case 22 from the above considerations a pair cable will give better isolation from longitudinal noise. Figure 8 shows the measurement of ground noise. €[ 'V Figure 8. Measurement of Ground Noise m ? 01969