LABORATORY MANUAL of ORGANIC CHEMISTRY by DR. H. C. SCURLOCK PROFESSOR OF CHEMISTRY, HOWARD UNIVERSITY Printed for use in Howard University WASHINGTON, D. C. Beresford, Printer, 605 F Street, N. W. 1910 LABORATORY MANUAL of ORGANIC CHEMISTRY by DR. H. C. SCURLOCK PROFESSOR OF CHEMISTRY, HOWARD UNIVERSITY Printed for use in Howard University WASHINGTON, D. C. Beresford, Printer, 605 F Street, N. W. 1910 TO THE STUDENT. This little manual constitutes an introduction to the study of Organic Chemistry which shall aid the beginner to understand from the first the principles of the subject as they are presented. About forty exercises given here by no means represent the whole of the practical work in the laboratory. They are selected with the view of attaining the end already mentioned, and are the minimum requirement in any course in Organic Chemistry in this University at the present time. A written report upon each exercise is required, and students will be quizzed orally in groups or individually upon the same subjects, as well as meet them in the written examinations. To secure a passing grade there must be satisfactory evidence of understanding the subject matter to which these exercises have reference. Copyright, 1910, By H. C. Scurlock. ORGANIC CHEMISTRY. HYDROCARBONS. The simplest organic compounds are the hydrocarbons— bodies which contain carbon and hydrogen only. Some chemists look upon all other organic compounds as deriva¬ tives of the hydrocarbons, and define organic chemistry as the chemistry of the hydrocarbons and their derivatives. While the large number of substances studied in inor¬ ganic chemistry have their origin in the various combina¬ tions of all the elements, the thousands of known organic substances are composed chiefly of only four elements. They all contain carbon and hydrogen, many of them con¬ tain oxygen and nitrogen, while sulphur and phosphorus are also found sometimes. It is not to be understood, however, that no other elements ever enter into organic compounds. Hydrocarbons are divided into two principal classes— the open chain, or acyclic, and the closed chain, or cyclic. By a chain is meant the linking of several atoms together as a nucleus from which compounds may be built up. Carbon is the chief element in organic substances, and is the element which forms the chains giving rise to the bodies studied in organic chemistry. An open-chain hydrocarbon is one, the nature of which is such that other carbon atoms may be made to enter it, thus increasing the carbon content and forming a new nucleus whose properties are different from those of the 4 original nucleus. For example, ethane is C2H6, having two C atoms in the nucleus. It may be changed to pro¬ pane, C3H8, having three C atoms in the nucleus in the following manner : Treated with bromine, ethane will yield brom-ethane H H I i H —C —C—Br, I I H H which, treated with methyl bromide and metallic sodium, will add on C. H H H H H H — C — C—jBr + Br | | ! +2Na H H CH3=H— C— C —C —H + 2NaBr. H H H In a closed-chain hydrocarbon no additional carbon atoms can be made to enter into the original group. By Fittig's synthesis, benzene, which is usually represented by a closed hexagonal ring, can be changed into a compound having seven carbon atoms, C7H8. But it can be proved that the additional C atom does not enter the ring, but is attached as a side chain. Hydrocarbons are said to be saturated when only one bond of affinity links the C atoms; they are unsaturated when more than one bond of attachment exist between any two C atoms. H H H H H III. II H H—C—C—C—H H—C—C=C I h2o J 1 J- of Ammonium NH( CnH2n+2, saturated. l-nH2n "I CnH2n—2 ! Unsaturated: May be absorbed CnHan—6 j by Br or fuming, H2S04. CnH2n-r-i2 J ( Non-illuminants. Traces of O, CS2, etc. 7 Hydrocarbons occur in series, the successive members differing by CH2—homologous series. Their derivatives also form homologous series. HOMOLOGOUS SERIES. Hydrocarbons. Alcohols. Acids. (General formula, (General formula, (General formula, cnh2n+2). CnH2n+i.oh). cnhznoa). ch4 ch3.oh ch,o2 c2h6 c2h5.oh c2h4o2 c3h8 c3h7.oh c3h602 etc. etc. etc. The members of a homologous series are often spoken of as the homologues of the first member or of a principal member; thus> pentane is a homologue of methane ; pro¬ pionic acid is a homologue of acetic acid. The two series of hydrocarbons yielding the largest number of important compounds are the paraffin and the benzene series. The members of the paraffin series are found chiefly in petroleum, while benzene is a product of coal tar obtained in the distillation of coal. (See tables on pages 5 and 6.) Hydrocarbon radicals, which are the " elements" of or¬ ganic chemistry, are formed by the removal of hydrogen from the hydrocarbon: Saturated Univalent Bivalent Trivalent hydrocarbon. radical. radical. radical. CH4 methane. —CH3 methyl. =CH2 methylene. =CH methenyl. C2H6 ethane. —C2H5 ethyl. =C2H4 ethylene. =c2H3 ethenyl. The univalent radicals of the paraffin hydrocarbons are called alkyls; their general formula is CnH2n+I. Thus the expression " alkyl halide" would mean a body of the composition CnH2n+I.X, where X stands for a halogen. Empirical or molecular formulas are of very little use in organic chemistry, and it is important that structural and graphical formulas be learned. Structural formulas. C2H5OH, or, CH,.CH,OH Alcohol. CHo.O.CH,, or, (CH3)20 Methyl ether. Graphical formulas. H H II C H H-C — C—OH °r pj >0 H H Alcohol. CH3>0 CH >° Methyl ether. The molecular formula C2H60 may mean either alcohol or methyl ether, but in either case, written as above, there could be no mistake. Classification.—In inorganic chemistry we were con¬ cerned with binary and ternary compounds, including acids, bases and salts. We shall find compounds of analogous composition in organic chemistry. Alkyl halides, R.X CH3CI, methyl chloride. Alkyl hydrates (alcohols). R.OH C2H5.OH, ethyl hydroxide (grain alcohol). Alk-oxides (ethers), >0 CA>0. ethyl oxide (ether). CH3.C<^^, acetaldehyde. CH, Aldehydes, R.C<° Ketones, r>C—O ^^3>C=0, dimethyl ketone (acetone). Acids, R-C methyl carboxyl (aceticacid). Amines, R.NH2 C2H5.NH2, ethyl-amine. Amides, -O T T , acetamide 9 This list by no means includes all the classes of organic compounds, but is sufficient to show the relation of the hydrocarbon radical in the constitution of substances. Derivatives of the paraffin series and the homologues of methane are often referred to methane as the parent sub¬ stance, or nucleus; thus, pentane C5H12 would be tetra- CH3 i methyl methane, H3C—C—CH3; alcohol could be called CH3 ch3 i hydroxy-methyl methane, H—C—OH. I H It is readily understood that methane (CH4) is the simplest of the paraffin hydrocarbons, and if an acid (for example) were to be formed by writing the carboxyl group joined to an R we should not have a product corresponding to the simplest member, but the next higher. Then, in writing the formulas of the first members of homologous series of compounds, such as alcohols, aldehydes and acids, which have characteristic groups of atoms, H is placed where otherwise a hydrocarbon radical would appear. H—CH,OH H—C<° H—C<°H Methyl alcohol. Formaldehyde. Formic acid. CIIj—CH,OH CHs-C<£ CH,-CC = 0. The formula of acetone is ^^3>C = 0 (di- 23 methyl ketone). When oxidized it produces acetic acid and formic acid, the latter, however, being further oxidizable to carbon dioxide and water. ETHERS AND ESTERS. 18. Ethyl Ether .—Put 50 c.'c. each of alcohol and con¬ centrated sulphuric acid in a flask which is closed with a stopper carrying a dropping funnel and a thermometer. Connect the flask with a condenser, and cover the receiver with a wet cloth to keep it cold. Heat the contents of the flask to a temperature of about 130 degrees. When ether begins to distil over, slowly add more alcohol through the funnel. Collect the distillate and add an equal volume of water; pour into a separatory funnel and agitate. When the two liquids separate run out the water. Shake the ether with dry calcium chloride and distil. Small quantities of concentrated sulphuric acid are capable of trans¬ forming relatively large quantities of alcohol into ether. Williamson's theory of etherification is expressed in the following equations : C2H5OH + H2S04 = C2H5HSO4 + H20 C2H5OH + C2H5HS04 = (C2H5)20 + H2SO4 Care.—Remember the caution given under " Extraction with Ether." Ethyl Acetate.—Pass dryhy drochloric acid gas into a mixture of glacial acetic acid, 25 c.c., and absolute alcohol, 40 c.c. Heat the mixture for an hour in a flask connected with a reflux condenser. Transfer to a fractioning flask and distil. CARBOHYDRATES. The carbohydrates include the sugars, starches and cell¬ ulose, and are classified as mono-, di-, tri- and poly- saccha- rids. The mono-saccharids are the simplest sugars; di- and tri-saccharids split up into two and three simple sugars, respectively; the poly-saccharids are not so easily changed into sugars. Sugars contain an alcohol group and an alde¬ hyde group, or a ketone group, to which many of their reactions are due. 24 Monosaccharids containing five, six, seven, etc., carbon atoms are called pentoses, hexoses, heptoses, etc., respec¬ tively. PROPERTIES OF THE MONOSACCHARIDS. 20. Reduce ammoniacal solutions of silver.—Use a solu¬ tion of glucose and make test with ammoniacal solution of silver as given in 14, under aldehydes. 21. Reduce Fehling's Solution.—Use solution of glucose. 22. Resinify with caustic alkalies.—Boil a solution of glucose with a small quantity of a solution of caustic soda. 23. Furfuraldehyde test for Pentoses.—Dissolve 3 or 4 c.c. of concentrated sulphuric acid in about 75 c.c. of water. Put into a flask and add 10 grams of bran. Distil; the distillate gives the odor of furfuraldehyde. 23a. Identify furfuraldehyde as follows : Add a little aniline to the distillate, then treat with concentrated hydrochloric acid. It gives an intense red color. 24. Hexoses. Hydrochloric test.—Boil a solution of glucose with concentrated hydrochloric acid. A brown, amorphous substance is deposited and laevulinic acid re¬ mains in the solution. PROPERTIES OF SACCHAROSE. 25. Apply tests 20, 21 and 22, under monosaccharids. The reactions are negative. 26. Inversion of Saccharose.—Dissolve three grams of cane sugar in water and boil with dilute sulphuric acid for about 15 minutes. Neutralize with solution of soda, and apply tests 20, 21 and 2 2. Reactions are positive. POLYSACCHARIDS. 27. Starch.—Agitate a small quantity of starch with cold water, to wash it, and filter. Be sure that it is washed well and then make with it starch paste. Use this paste for tests 20, 21 and 22. The reactions are negative. 25 28. Conversion of starch to glucose.—Boil 30 c.c. of starch paste with dilute sulphuric acid for about 20 min¬ utes; neutralize with soda solution and apply tests 20, 21 and 22. The reactions are positive. THE PURIN BODIES. Certain chemically related substances occurring in the animal and plant world, among them uric acid, xanthine, theobromine, caffeine, etc., are looked upon as derivatives of the " purin ring." N= CH HN—CO II II HC C—NH CO C—NH II II >CH. | || >CO. N—C— N HN—C—NH Purin ring. Uric acid. N (CH3) —CO I I CO C—N (CH3) I II >CH. N (CH3) - C N Caffeine. Caffeine occurs in coffee ; theobromine is found in cocoa. The relation of urea, the principal nitrogenous constituent of the urine, to uric acid is indicated in the following re¬ action : C5H4N4O3 + H20 + O = (NH2)2CO + C4H2N204. Uric acid. Urea. Alloxan. 29. Murexid test for uric acid.—Mix 5 c.c. of nitric acid and half a gram of uric acid in an evaporating dish and evaporate over a water bath almost to dryness ; treat the residue with ammonium hydroxide. It will give a pur¬ ple-red color. 30. Murexid test for caffeine.—Apply test as for uric acid, using caffeine in the place of uric acid. 26 CLOSED-CHAIN HYDROCARBONS. The closed-chain hydrocarbons differ from the open chain in several respects. Open chain. Not easily acted upon by nitric or sulphuric acids. Not affected ordinarily by oxidizing agents. Hydroxyl-derivatives are of a basic character. Closed chain. Easily form nitro-deriva- tives with nitric, and sul- phonic-derivatives with sulphuric, acid. The homologues of benzene are oxidizable. Hydroxyl-derivatives are of an acid character. ACTION OF NITRIC ACID. 31. Nitrobenzene.—Put into a flask a mixture of 1 part nitric acid and 2 parts (by volume) of sulphuric acid. Slowly add about 1 part of benzene. Keep the flask cold with running water. When the benzene has dissolved pour the mixture into water. The heavy nitrobenzene will sink to the bottom. Separate from the upper layer and notice the odor of bitter almonds. ACTION OF SULPHURIC ACID. 32. Benzene-mono-sulphonic acid.—Gradually add 5 c.c. of benzene to 10 c.c. of fuming sulphuric acid. Heat gently for a few minutes, and then pour the reaction mix¬ ture into about 30 c.c. of cold water. Stir in some common salt until fumes of hydrochloric acid are given off. When cold, crystalline plates of sodium benzene-sulphonate, a salt of benzene-mono-sulphonic acid, will separate. Friedel and Craft's Reaction.—This is one of the most important synthetic reactions and is peculiar to the benzene series. By its use a great many compounds have been built up easily which probably other¬ wise would not yet have been synthesized. The synthetic agent is aluminum chloride. 27 33* Triphenyl-methane.—Perform this experiment un¬ der the hood. Make a mixture of i gram of aluminum chloride and 5 c.c. of benzene ; then gradually add a little chloroform. Hydrochloric acid is given off vigorously, in the meantime tri-phenyl-methane is formed. (C6H5) 3C,H# + CHCI3 = H—C—(C6H5) + 3HCI. (C6H5) Triphenyl methane gives rise to many important dyes, e. g., methyl violet, aniline blue, malachite green, rosaniline, magenta, rosolic acid, etc. 34. Oxidation of side chains.—Heat 2 c.c. of toluene with a solution of potassium permanganate until the purple color is discharged. The precipitate is manganese diox¬ ide. Filter, acidify with sulphuric acid, and allow to cool. Crystals of benzoic acid will separate. BENZENE DERIVATIVES. Phenol is hydroxy-benzene, that is, benzene in which an atom of hy¬ drogen has been substituted by hydroxyl. It is commonly known as carbolic acid. 35. Trinitrophenol.—Cautiously drop into 10 c.c. of nitric acid about one c.c. of phenol, meantime shaking the flask, then heat to boiling. Picric acid is precipitated upon cooling and crystallizes from hot water in yellow, needle-like crystals. Compare this action with the action of an acid on the hydroxyl-deriv- ative of an open-chain hydrocarbon, for example, the action of nitric acid upon amyl alcohol. The result would be the formation of an ester, amyl nitrite, by the replacement of the OH of the alcohol by the radical of the acid. Here the nitro group replaces H of the nucleus, giving tri- nitro-phenol—picric acid. 36. Amino-Compounds. Anilin.—Put into a flask 10 c.c. of nitro-benzene and add 30 c.c. of hydrochloric acid. Add to this 15 grams of powdered tin, in portions of about 1 28 gram at a time. After each such addition shake the flask and immerse in water to keep it cool. When the odor of nitro-benzene is no longer perceptible add a solution of caustic soda. Distil with steam, as shown in figure 5. Ex¬ tract the turbid distillate with ether; separate in the sepa- ratory funnel; dry the ethereal extract with sticks of caustic potash; evaporate the ether and then distil from a small fractioning flask over a free flame. Anilids are salts of anilin in which an atom of H in the amino group is replaced by an acid radical. Acetanilid is such a salt, in which the acetic acid radical is substituted. 37. Acetanilid.—Boil together in a flask fitted with a reflux condenser equal volumes of anilin and glacial acetic acid (not more than 15 c.c. of each). The operation will require several hours. The mixture when cold deposits crystals of acetanilid. Benzaldehyde.—Benzaldehyde responds to the tests for aldehydes already learned under open-chain derivatives. 38. Make the silver-mirror test, using 2 drops of benzal¬ dehyde. 39. Benzaldehyde oxidizes to benzoic acid. Heat a little benzaldehyde with a solution of potassium permanganate. Should the color of the permanganate persist after the odor of the benzaldehyde has disappeared, add a drop or two of alcohol—only enough to discharge the color. Filter, acidify and allow to cool. Benzoic acid is precipitated.