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Hi I "ii : ' rtttm ' Hftmtmmi . iiutnimi ( rr,,i ■ .in-; IflKUl!H we can write down the first v O-L law of thermodynamics for perfect gases as follows : T>rp dQ = C v dT+—dv (1) From equation (1) we can eliminate v or T by means of the relation pv = RT, and obtain dQ = (C v + B)dT-—dp .... (2) and dQ = ^vdp+^±^pdv (3) Equations (1), (2), (3) represent three ways of stating mathe- matically the first law of thermodynamics in the case of a perfect gas. They differ from each other only in the selection of the co-ordinates. These expressions contain two physical constants of the gas, viz., C v = specific heat at constant volume, and E. Both these constants must, of course, be determined experimentally. The quantity C v being difficult to determine experimentally, it is preferred to put these formulse into a different form, containing O p — specific heat at constant pressure. REVERSIBLE CYCLES IN OASES AND VAPORS. 15 To bring out the meaning of this physical constant, and show its relation to C v , suppose that we have a unit weight of air enclosed in a cylinder by means of a piston, which can glide up and down the cylinder without friction. Its tem- perature, volume, and pressure being T, v, and p, we must have pv = RT. Clamp the piston, and apply heat to the gas until its temperature rises by dT. Let dQ l be the mechani- cal measure of this heat communicated to the gas during this operation; then dQ 1 = d ^dT=C v dT. Now loosen the clamp, the volume will increase, since the temperature is now T -\- dT. During this second operation communicate heat to the expanding gas so as to keep its tem- perature constant. The volume will expand from v to v-\-^-^dT, overcoming pressure^?. Observe that — 7=, represents the rate of variation of volume due to variation of temperature, the pressure being constant. Hence from pv = RT we obtain dT~ p- Let dQ, be the heat communicated during this second operation; then dQ,=p^dT=RdT. *Q t + *G, = (C + X)dT. 16 THERMODYNAMICS OF At the end of these two operations we have a change in tem- perature — dT, a change in volume = ^TpdT, and external work equal to p^^dT. Consider now another process, by means of which the same change in temperature, the same change in volume, and the same external work is produced. Let us call the rate at which heat must be applied to the unit weight of the gas, when it expands at constant pressure, C p . Apply heat until the same change in volume is produced as before; the final temperature will be T -\- dT, as before. The pressure in the second case being the same as in the first, we shall have the same external work clone during the expansion, and the in- crement in internal energy will also be the same, since the change of temperature is the same; hence the quantity of heat communicated will also be the same. Call it dQ ; then dQ = C p dT. But since dQ = dQ t + dQ* , we must also have C P =C V + E or C v = C p - R. Substituting in equations (1), (2), (3), we obtain TIT dQ = (C p -R)dT+^dv>, . . . (i») TIT dQ=C p dT-^dp; ...... (2«) dQ = ^—vdp+^pdv (3") REVERSIBLE CYCLES IN OASES AND VAPORS. 17 The Eatio of Specific Heats. We will now introduce a new constant, namely, —f=k. This physical constant of a gas was first introduced by Reg- nault, and is of vital importance, for the reason that k can be determined experimentally with great accuracy by determin- ing the velocity of sound through the gas. Regnault found k for air = 1.41. C p we can also determine by experiment; hence we can cal- culate R. Vice versd, if R and C^are determined experimentally, then both C„ and k can be calculated. The relation P = R — O v , as it stands, applies to values of these physical constants measured in mechanical units. Divid- ing by J — the mechanical equivalent of heat — we obtain C p R O v ~J~ J ~J' or „ R Op — j c v> where c p and c v are measured in kg. calories. Calculation of the Mechanical Equivalent of Heat. An interesting relation is obtained from the last equation. Remembering, namely, that -=f = k, we obtain /= T - r- . U (« — l)'-p 18 THERMODYNAMICS OF This is the relation first pointed out by Robert Mayer, and actually employed by him to calculate J. Before we can apply it to any gas, we must find the value of B. Let us find the same for air. U ~ 273 * Regnault found that at the barometric pressure of 760 mm. the value for v t of one unit weight of air is .7733 cubic meters. But since our units are kilogrammes and meters, we have to change the above value of p accordingly. The specific weight of mercury used by Regnault is 13.596; we get therefore p — lOO" 3 *" X 7.6*" x 13.596 = 10333 kg. per square meter. Hence, since v a = .7733 cubic meter, i2 = 10333_X^733 = 29 ^ The values of h and c p for air were determined by Reg- nault. They are k = 1.41, c p = .2375. Hence we obtain T 29.27 X 1.41 .„.. .41 X .2375 = kg.-meters. The value of J obtained by direct experiments is very nearly 424. So much for the physical constants of a perfect gas. REVERSIBLE CYCLES IN GASES AND VAPORS. 19 A table of c v and c p for various gases will be given pres- ently. To sum up: The mathematical statement of the first law of thermodynamics in the case of perfect gases expresses a quantitative relation between the increments in volume, pressure, and temperature of a gas when a small quantity of heat d Q is added to or taken away from it. This relation contains the physical constants R, G p , C v , k, which must be determined by experiment. Experiment tells us that C p , just like R, is independent of pressure and temperature. Hence G v and Tc are also independent of these. This makes the thermodynamic study of the behavior of perfect gases com- paratively easy. It is well now to consider how we can apply the first law of thermodynamics to the solution of a few simple problems. Problems. We shall consider two problems in particular : (1) We shall determine the amount of heat absorbed by a gas when it expands under constant pressure. (2) We shall determine the amount of heat absorbed by a gas when it expands at constant temperature. To solve these equations we must observe that a proper selection among the three mathematical statements of the first law of thermodynamics will afford us considerable mathe- matical advantage. For the first problem we select one of the formulae, con- taining v and p as independent variables, and since p in this 20 THERMODYNAMICS OF case is to be constant, the term containing dp becomes zero. Hence dQ = — £-5 — vdp -\- -£pdv becomes dQ = HjLpdv. Integrating from v = v t to v = v, , we get § = fdQ = %pf v ° % av = & P {v t - »,). Numerical Example. — Consider a kilogramme of air at barometric pressure of 760 mm. ; that is, let the initial press- ure be 10333 kilog. per square meter, let the initial volume be .7733 cubic meter, and let i> 2 = 2v r Since c p =.2375 kg. calories, and C p = .2375 X 424, therefore the amount of heat absorbed by the gas while expanding under constant pressure from v l to 2v 1 will be Q = 10333 X. 8375 X 484 x ^ = ^ ^ ^ 27490 , = - 1 g r kg.cal. In the second problem, where we wish to determine the amount of heat that must be supplied to the gas in order to expand it under constant temperature, we take the formula (l a ) dQ=(C p -B)dT+ — dv, REVERSIBLE CYCLES IN GASES AND VAPORS. 21 because there <1T being zero, when T is constant, we obtain dQ=^-dv, and hence Q = RT J *— = RT log \ which is the total amount of heat measured in kg. meters which is absorbed by the gas while expanding isothermally from volume v x to volume v v To determine the total amount of work done, we put W= / pdv = RT — = RTlog -\ This result, compared with the preceding one, gives an identity. It tells tts that the entire amount of heat put into the gas was utilized to do external work ; for since the temper- ature remains constant, none of the heat supplied goes to in- crease the intrinsic energy of the gas. Isothermal and Adiahatic Curves. If we make the supposition that during the expansion of the gas the temperature remains constant, we have from Ma- riotte-Gay-Lussac's law pv = (J. Represent this result graphically, taking p for ordinates and v for abscissae. The resulting curve is an equilateral hyper- bola refer-red to its asymptotes. Such a curve is called an iso- thermal curve. (Fig. 1.) There is evidently an isothermal curve for every tempera- ture; hence an infinite number of them, but every one of them is an equilateral hyperbola in the case of a perfect gas. 22 THERMODYNAMICS OF Tlie isothermal curves of a perfect gas form a system of curves which never intersect. For suppose there is a point where two curves do intersect, this would have to he a point where at different temperatures the pressure is the same for the same volume, — which is absurd. Fig. 1. Fig. 2. Let us suppose again that we diminish the pressure without introducing additional heat. The piston will go up, hence the temperature will diminish; and as soon as a point is reached where pj\ — RT 1 the expansion will cease. If we plot a curve expressing a relation between p and v at any moment during this expansion, we get what is called AN ADIABATKJ Or ISENTROPIC CURVE. (Fig. 2.) The equation of this curve will be deduced presently. Equation of the Adiabatic Curve of a Perfect Gas. Since no heat is communicated during an adiabatic expan- sion, the following relation must exist at any moment between the physical constants of the gas : RT {C p -R)dT+*-^-dv. (R - C p ) log |f = 22 log V f, REVERSIBLE CYCLES W OASES AND VAPORS. 23 or Let us illustrate this by an example. Suppose the initial temperature is 0° 0. above the freezing- point, and a certain initial volume of a kg. of air is com- pressed to £ the volume ; calculate the rise in temperature. T x = 273, ^ = 2. .-. |L = (2)-* 1 = 1.329, or T, = 363° C. Hence t,= T,— 273 = 90° C. above the freezing-point. Compressing the initial volume to £, we find t - 209° C. Compressing the initial volume to -fa, we find t = 429° C. We shall noiv calculate the external work done, when the gas expands adiabatically. From pv — ETwe get £« = =£» -*. But we found ^ = (M*~\ ^ ) , or, more generally, p = ^-. 24 THERMODYNAMICS OF The last equation is the equation of an adiabatic of a perfect gas. It is evidently of the form const. 9 = ~7S— To calculate the external work done during an adiabatic expansion from volume v 1 to v 2 , we have = R .{T — T). A family of adiabatic curves never intersect each other, but every adiabatic curve intersects every isothermal curve. The axes of p and v are asymptotes to the adiabatics of a perfect gas, but the adiabatic passing through a given point is more, steeply inclined to the p axis than the isothermal passing through the same point. Summary. It has been shown so far that heat is a form of energy, and that therefore it obeys the Principle of Conservation of Energy. The constant ratio at which it is convertible into mechanical energy is 424; that is to say, if the quantity of heat which must be supplied to the unit mass of the standard substance (one cubic decimeter of pure distilled water at 4° C. and 760 mm. barometric pressure) in order to raise its temperature 1° C. be called a unit of heat, then this unit of heat is equivalent to 424 mechanical units of work, the weight of the unit mass at REVERSIBLE CYCLES IN OASES AND VAPORS. 25 a definite place, that is, the kilogramme weight, being taken as the unit of force and the meter as the unit of length. Briefly stated, the mechanical equivalent of a kilogramme calorie is 424 kilogramme-meters. After that it was shown that if we add a quantity of heat to a body that heat will appear partly as an increment of the intrinsic energy of the body and partly as external work. For very small quantities of heat this can be stated as follows : dQ-dU. + dU^ + dW, which is the most general form of the First Law of Thermo- dynamics. In this equation dU 1 is the increment of the in- trinsic energy due to increase of the sensible heat of the body, and d Z7 2 is the increment of the intrinsic energy due to the increment of internal potential energy of the body. The ex- ternal work dWwa,s shown then to he pdv, as long as we limit ourselves to a particular kind of external work, that is, work done by the body in expanding against a uniform, normal surface pressure. Limiting ourselves to such physical processes in which the state of the body, which is the seat of these processes, can be described completely at any moment by temperature, vol- ume, and pressure, it was shown that the first law of thermo- dynamics can be stated as follows : «e- 8 !* +(£+*)* The application of the first law of thermodynamics to the study of such physical processes in various classes of physical 26 THERMODYNAMICS OF bodies was then in order. We commenced with the simplest class of physical bodies, that is, with perfect gases. Starting with the Boyle and the Mariotte-Gay-Lussac Laws, and re- membering that the intrinsic energy of a perfect gas is inde- pendent of its volume, we showed that the First Law of Ther- modynamics for perfect gases can be stated as follows : dQ= C v dT + pdv, when G v is the specific heat of the gas at constant volume, measured in mechanical units. By the relations G p = C v + R and pv = RT we then gave the various forms of statement of the above equation, these various statements differing from each other in the selection of the independent variables p, v, and T, and the physical constants C p , C v , R, and k. An important observation was then made, and-that was, that ac- cording to Regnault's experiments, O p , and therefore C v , R, and k, are the same for all temperatures, volumes, and press- ures at which the gases retain their characteristic properties of a perfect gas. The application of these various forms of statement of the First Law of Thermodynamics for perfect gases was then made, and the isothermal and adiabatic changes of such gases dis- cussed. We ended with the discussion of isothermal and adia- batic or isentropic curves of a perfect gas. We could, following the same method of discussion, apply now the first law of Thermodynamics to the study of physical processes of above description in the case of any other class of physical bodies. It is evident, however, that since the fun- damental relation between pressure, volume, and temperature REVERSIBLE CYCLES W GASES AND VAPORS. 27 in the case of physical bodies in general is far from being as simple as in the case of perfect gases, — it is evident, we say, that our discussion would lead to very complicated equations, involving physical constants which, in very many cases, have not as yet been determined experimentally. We shall there- fore abstain from a general discussion, but pass on to the application of the first law of thermodynamics, to the study of reversible processes in vapors. This class of bodies is ex- tremely important, particularly from an engineering stand- point, because it is the action of heat upon these bodies that is generally employed as a means of transforming heat energy into mechanical energy, and vice versd. Before making this next step, it is advisable to deduce another general law, which, like the first law of thermody- namics, underlies all reversible heat processes in nature. It is called the Second Law of Thermodynamics. We close now this part of our course with a discussion of the various methods of expressing the specific heats of gases, and the relations which exist between them. On the Vaeious Wats of Expressing the Specific Heats of Perfect Gases. Consider the relation c p = c v -\ — j . This relation says : Given the spec, heat of a gas at con- stant pressure, the spec, heat at constant volume can be calculated, if the constant R of the gas, and the mechanical equivalent of heat, are known. We mentioned previously that we could determine the 28 THERMODYNAMICS OF ratio of the spec, heats by means of the velocity of sound. This gives another method of calculating c„ when c p is known. But it is very difficult in some gases to determine (k) by velocity measurements. In such cases we must take our recourse to the above formula. R can be calculated from the formula K ~ 273' It is possible, nowever, that the gas cannot oe well observed at the freezing temperature; hence we must look for another method of calculating R. We can write in every case 7?-P v At the same temperature and pressure we shall have for the same weight of a standard gas, say well-dried air, R' '=■££. Hence R = R' 4-. 1 v V The fraction -7- is the reciprocal value of the spec, weight of the gas, that is of its density, the density of air being taken is equal to unity. Calling this spec, weight, that is, the density, d, we have d REVERSIBLE CYCLES IN GASES AND VAPORS. 29 By substituting this value of R iu the first equation, we get R' 1 R' in our case is 29.27. Example. Calculate c v for air. d=l, hence c„ = .2375 - IMi = .1684. 424 Z - * - J68T - L4L That is to say, to raise the temperature one degree, a kilog. of air requires only about -§- of the heat that a kilog. of stand- ard water does. The spec, heats denoted by c p and c v refer to a unit weight of the gas, and their unit is that quantity of heat which is necessary to raise the temperature of a unit mass of standard water under standard conditions one degree; that is, in other words, the gas is compared calorically by weight, to water. While, as a matter of fact, it is sometimes more convenient to compare in this respect gases with air, by considering equal volumes, i.e., to determine the spec, heat in such a manner, that the amount of heat necessary to raise the unit volume of a gas one degree, is compared with the quantity of heat necessary to raise a unit volume of air through one degree (at the same temperature and pressure). We can employ that method of comparison for both specific 30 THERMODYNAMICS OF heats, considering in one case that the gas and the air are heated at constant pressure, and in the other that the gas and air are heated at constant volume. Let the volume of a unit weight of gas be v. The amount of heat which a unit volume must get to raise its temperature one degree at constant pressure must there- fore be v Let the volume of a unit weight of air = w, , then the amount of heat necessary to raise a unit volume through one degree under the same conditions will be -% = / v The ratio of these quantities evidently gives us y p ; that is, the quantity of heat necessary to raise the temperature of the unit volume of a gas at constant pressure measured in terms of the heat necessary to raise the temperature of the unit volume of air under the same conditions. Hence 'p — *,' — -' ■>, ~ „> Similarly, y c p v c- p REVERSIBLE CYCLES IN OASES AND VAPORS. 31 TABLE OF SPECIFIC HEATS OF GASES. Air Oxygen Nitrogen Hydrogen Chlorine Carb. monoxide. . Hydroch. acid gas. Carbonic acid Steam Ammonia Alcohol Ether 2 N a H 2 Clj CO HC1 C0 2 H 2 NH 3 CnH 6 C 4 H 10 O Density . 1. 1.1056 0.9713 0.0692 2.4502 0.9673 1.2596 1.5201 0.6219 0.5894 1.5890 2.5573 Specific Heat at Const. Pressure. 0.2375 0.21751 0.24380 3.40900 0.12099 0.2450 0.1852 0.2169 0.4805 0.5084 0.4534 0.4797 1. 1.013 0.997 0.993 1.248 0.998 0.982 1.39 1.26 1.26 3.03 5.16 Specific Heat at Const. Volume. 0.1684 0.1551 0.1727 2.411 0.0928 0.1736 0.1304 0.172 370 0.391 0.410 0.453 1. 1.018 0.996 0.990 1.350 0.997 0.975 1 55 1.36 1.37 3.87 6.87 III. SECOND LAW OF THERMODYNAMICS. Oaknot's Kbvbrsible Engine and Carnot's Cycle. Let ns start with a process of expansion and compression of a perfect gas enclosed in a cylinder which is impermeable to heat. The piston which shuts the gas in, can glide up and down without friction. The piston being under a given pres- sure, the gas will at a given temperature occupy a definite volume. Heat can be communicated to the gas through plug p. Let the length oe on the abscissa denote the original volume v of a gas, and the ordinate ea the initial pressure p . Evidently these two conditions determine the tempera- ture of the gas at that moment. Let the gas expand isother- 32 THERMODYNAMICS OF mally. To accomplish this imagine it connected to a large reservoir A (Fig. 4) of temperature T 1 , the same as that of the gas. By gradually diminishing the pressure and expanding H3 =c Fig. 3. Fig. 4. very slowly, the temperature will remain constant and equal to T . Plotting the curve expressing the relation between p and v, we get a part of an isothermal curve. Point b indicates the volume and pressure at the end of the isothermal expan- sion. Now cut off the heat reservoir A, and let the gas ex- pand slowly still further (by diminishing the pressure), but of course adiabatically, that is to say, the gas expands and decreases in temperature on account of loss of heat due to external work done. The curve of expansion, be, will be a part of an adiabadic. Call the temperature, when volume v 2 has been reached, T r From now on compress the gas, but having first connected the cylinder to a reservoir B of tem- perature T 2 and of so large a capacity that it will take up all the heat from the compressed' gas without changing its temperature perceptibly. The heat generated in the gas by compression will be given off to B, hence the compression will be isothermal. The curve of compression will again be REVERSIBLE CYCLES IN GASES AND VAPORS. 33 a part of an isothermal. At this point we impose a. particular condition, namely, that the gas be compressed until a point is reached where the isothermal cuts that adiabatic curve winch goes through the starting point a. Arrived at that particular point, we disconnect the reservoir B and continue the compression. From there on the gas is compressed adiabatically, the temperature rises, and when the original temperature T t has been reached the gas will evi- dently have the same volume and will be under the same pressure as at the beginning. These four operations con- stitute what is called a Garnot Cycle. Now we shall consider the work done by the gas and upon the gas during the various operations in the cycle. The work done during the first expansion can be represented by the area abfe, that during the second by b cgf. During the compressions work has been spent upon the gas equal to the areas cdhg and hdae respectively. The difference between the work done and the work expended is the work gained. This gain must evidently be at the expense of heat given up to the gas by the reservoir A. Heat was taken up from A by the gas during the first operation; let us call that Q i; and during the isothermal compression heat was given out from the gas to the reservoir B; let us call that Q t . Since on the whole a certain quantity Q was transformed into work represented by the area abed, it is evident that Q, = & + Q- Let us illustrate that method by an example. 34 TEESMODTXAinCS OF Say that we hare .5 kilcgr. of air, and an initial pressure of 10 atmospheres, that is equal to 7600 mm. barometric pressure or 103,330 kilogr. per square meter. Let the initial volume be ^ cubic m. i\ = .1 cm. p i = 103,330 klg. per sq. m. Weight = .5 kg. 2/w, = RT^ . „ 103330 X .1 X 2 • ■ T i = on oy = ,06 Suppose now fhat we work between the reservoirs A and B at 706° and 293° respectively. Hence T ± = 706°, y s = 293°. We will proceed by allowing the gas to expand isothermally. until the volume is equal to ;•, , and suppose for convenience of calculation v It=e = 2.72. Work done by the gas during this expansion = / pdv= J*'. J v x RBVERSIBLB GTOLBS IN OASES AND VAPORS. 35 But in isothermal expansion pv = RT l = constant. .-. W, = RT> -- = RT X log ^ = 29.27 X 706 kg. meters. Jv, v V l Heat taken up from A will be = — '^—- — kg. calories. 424 ° Passing to the second operation we expand the gas from now on adiabatically, until its temperature is 293°. The final volume will be v 3 . Let the work done during this operation be denoted by W t , then W m K — I v& v ' p V But during this operation p — ~- 3 . = 29,480 kg. meters. Compress now isothermally until the point is reached where the isothermal cuts the adiabatic which passes through the starting point p l v 1 and denote this work of compression by W,. Then if v t be the final volume, W, = RTJog°f. 36 THERMODYNAMICS OF (v \* _1 T (v \ k_1 T . But since I - 4 j = -=±, also I -M = -+, it follows that ^^ov^=%.;lo g ^=-lo S ^;,.W 3 =-RT,hg\ v l v a v s v, & v 3 & «/ s «\ Similarly the work done during the last adiabatic compression will be W A R k ri( y . - T >) = - w* The total external work represented by the area abed is W= W t + W t + W % + W t = Rlog V -y i -T 1 ). W Efficiency = -=- _ T x - 7, This relation expresses the second law of thermodynamics. but only in a very limited form ; that is to say, this relation being simply a mathematical expression for the efficiency of a particular machine, Carnot's engine, operating in a perfectly definite manner, — that is, by simple reversible cycles, upon a particular class of bodies, namely, perfect gases, — this relation should not be considered to be anything more than it really is REVERSIBLE CTCLES IN OASES AND VAPORS. 37 namely, a law which holds true for a particular class of physi- cal processes taking place in a particular class of physical bodies. It was in this form that the great French engineer, Sadi Carnot, first discovered the law, seventy years ago, in 1824. But he did more than that. He also pointed out that it is only a particular form of a more general law, that is to say, a law which holds true for a class of physical processes much larger than the class we have just described. It was by a train of reasoning first suggested by Carnot's great essay, "Keflexions sur la puissance motrice du feu et sur les machines propres a la developper," that subsequent inves- tigators, and foremost among them Olausius and Eankine, were able to extend the above relation into a general law, called the second law of thermodynamics. Before proceeding any further in our discussion towards the generalization of the above efficiency relation into the second law of thermodynamics let us first examine carefully the foundation on which this relation rests. Consider each one of the four operations which taken to- gether constitute Carnot's cycle. Any one of them when reversed will produce just the opposite effect. Take for in- stance the second operation, that is, the first adiabatic expan- sion. If at the completion of this operation we reverse the operation, we can bring the gas back into the state which it had at the beginning of this operation. The reversed opera- tion will cost us mechanical work of compression equal to the area bcgh. That work will appear as intrinsic energy in the gas, that is, as heat, in consequence of which the temperature of the gas is increased from T^ to T,. If the first operation be 38 THERMODYNAMICS OF called the direct and the second the reversed, then we can say that the direct and the reversed operation just neutralize each other. The same is true of every other operation of the cycle. It follows, therefore, that the whole cycle can be reversed and the reversed cycle will produce just the opposite effect of the direct cycle, that is to say, it will deprive the reservoir B of Q 2 units and add Q 1 units of heat to reservoir A, and it will also transform Q 1 — Q^ = Q units of work into heat. In the first cycle heat passes from a hot body to a cold body, but some of this heat in its journey to the cold body is transformed into mechanical work and therefore never reaches the cold body. In the reversed cycle mechanical work is expended, in order to transfer Q 2 units of heat from the cold body to the hot, and in addition generate Q units of heat which are also given up to the hot body. Such a cycle is called a reversible cycle. The relation q _ y, - t, is evidently the same no matter whether the cycle be taken in the direct or in the reversed sense. Suppose now that during any one of the operations the gas had changed chemically, but in such a way that its chemical constitution could not be restored by reversing the operation. Such an operation would not be reversible, nor would the cycle of which this operation forms a component part be re- versible. In such a cycle the above relation may or may not be true. A special investigation is required to clear up this point; but since we are not going to discuss it in our course it is well that you should be told that it is not true. REVERSIBLE CYCLES IN GASES AND VAPORS. 39 It should also be observed that there are a great many reversible cyclic processes in all branches of physical sciences which do not apparently resemble Carnot's cycles of opera- tions. A great many illustrations may be cited from chem- istry, electricity and magnetism, etc. Whether in these Carnot's law of efficiency or the general form of it which we are about to deduce is applicable or not, must be decided by investigations which are outside of the limits of our course. What we propose to do is simply this : we are going to prove the applicability of Carnot's law of efficiency, and therefore of all its extensions, to all physical processes which consist of operations any one of which can be performed reversibly by a Carnot engine. The first step in our work will be to prove that the efficiency of a Carnot cycle depends on the temperatures of the reser- voirs A and B as expressed above, no matter what the sub- stance may be upon which we operate. To do this we shall start from an axiom first stated by Clausius, and therefore called the Axiom of Clausius. Heat cannot pass from a cold body to a hot body of itself. This statement includes, that by conduction of heat, or by concentration, reflection, etc., of radiant heat, no heat can be transferred to a body at the expense of a colder one, unless the process of transference involves the expenditure of some sort of energy. In the preceding discussion we saw that heat passed from a cold to a hot reservoir, but not without expenditure of work. 40 THERMODYNAMICS OF So we might say, instead of " of itself," " without work or compensation." The truth of this axiom is proved in the same way as the truth of Newton's axioms of motion, that is, by an appeal to experience. We shall now prove that the ratio between the heat trans- formed into work by a simple reversible cycle and the heat transferred from a hot body to a colder body during the same cycle is independent of the material which we employ in the cylinder of our ideal engine, and that it can depend only on the temperatures of the reservoirs A and B. For this purpose we employ two equal cylinders A and B containing two different substances, upon which we propose to perform simple reversible cycles. Each cycle is performed between the same tivo reservoirs, so that the temperatures be- tween which we operate are the same for each cycle. Perform now cycle I with the cylinder A, and suppose that a quantity of heat equal to Q is transformed into mechanical work, and that a quantity of heat equal to Q^ is transferred to the colder reservoir. Pass now to the other cylinder and perform a similar cycle, but in such a way that again a quantity Q of heat is transformed into mechanical work. A certain quantity of heat, say Q/, will be transferred to the colder reservoir. We wish to prove now that Q/ = Q^. For if it is not, sup- pose that Q/ > Q a . After performing cycle I in the direct order, by which a quantity of heat Q is transformed into mechanical work and Q^ transferred to the colder reservoir, employ cylinder B to perform cycle II in the reverse order, so that the mechanical work obtained by cycle I is retrans- formed into heat, and a quantity of heat equal to Q ' is trans- REVERSIBLE CYCLES IN GASES AND VAPORS. 41 f erred from the cold to the hot reservoir. At the end of the two cycles the only change that still remains is the transfer of a quantity of heat equal to Q/ — Q^ from the cold to the hot reservoir, that is, a transference of heat from a body of lower to a body of higher temperature without any compensa- tion. This is contrary to the axiom of Clausius, hence the supposition that Q/ > Q, must be dismissed. Next suppose that Q/ < Q^. We can prove that this sup- position also violates our axiom by going through cycle II in the direct and cycle I iu the reverse order. Hence Clausius' Axiom leads to the conclusion that Q/ = Q r That is to say, ivhenever mechanical vwrk is obtained at the expense of heat by a reversible cyclic operation, heat is transferred from a hot to a cold body and the ratio of the ivork obtained to the quantity of heat transferred from the hot to the cold body is independent of the substance which is operated upoti. That ratio will therefore be the same for a perfect gas as for any other substance. We proceed to calculate it for a perfect gas. Let the temperatures of the two reservoirs be 7', and T t and suppose that 7", > T t . We found previously that in the case of a perfect gas Q ._ y, - t % Q,~ t, ' or ft - Q+Q. -t | C,_ t x Q Q "*" Q t,-t; 9* - T > _ 1 - r « q r.-r, t,-t; 42 THERMODYNAMICS OF We see therefore that this ratio in the case of a perfect gas and therefore also in the case of any other substance depends on the two temperatures between which the cycle is performed. A slight modification of this relation will give us another form of stating the second law of thermodynamics applicable to simple reversible cycles. Prom this relation we obtain rp rp i rp • J 2 J ] ■ L t We obtained previously G, _ T x . Q T,-T,' e, Q T, t, - t; hence Combining this with the above we obtain & = & or £_ft- or «.+^e,_ — Q 2 is the heat given off to the cold reservoir by the sub- stance operated upon, hence — (— Q t ) or + Q^ can be said to be the heat received by the substance from the cold reservoir. With that mental reservation we can write down T, ^ T. REVERSIBLE CYCLES IN OASES AND VAPORS. 43 This is the more compact and at the same time more flexible form of stating the second law of thermodynamics applicable to simple reversible cycles. The English translation of this mathematical statement is : If in a simple reversible cycle the heats received by the substance operated upon be divided by the temperatures at which these heats were received and the quo- tients thus obtained be added together, then will the sum be equal to zero. This statement of the second law of a simple reversible cycle is certainly not nearly as clear nor physically as in- telligible as the other statement, which involved the efficiency of an ideal reversible engine, but, as will be presently seen, it enables us to extend in a very simple manner the applicability of this law to complex reversible cycles and thus give the second law of thermodynamics a much more general form. General Form of the Second Law of Thermo- dynamics. Complex Cycles. So far we have considered cycles between two temperatures only. We now proceed to extend this to a so-called complex cycle, that is, a cycle of operations between several reservoirs of different temperatures. We commence with three reser- voirs of temperature T lt T^, and T 3 . Let ab (Fig. 5) denote an isothermal expansion at the tem- perature T, , be an adiabatic expansion down to the tempera- ture T a , cd an isothermal expansion at the temperature T^ , de an adiabatic expansion down to the temperature T a , ef an isothermal compression at the temperature T t , the isothermal 44 THERMODYNAMICS OF compression to continue until the isothermal curve ef cuts the adiabatic through a, and lastly fa an adiabatic compres- sion to the starting point. During the expansions ab and cd the substance operated upon takes up the quantities of heat <2, , Q 2 from the reser- voirs A and B at temperatures T^ and T 2 , and during the Fig. 5. isothermal compression ef it takes up the negative quantity of heat — Q 2 from the reservoir at temperature T % . The external work done during the cycle is represented by the area abcdcfa. AVe proceed to show now that a similar relation holds true in this case as in the simple cycle. To do that, let us produce the adiabatic be until it cuts the isothermal fe at g ; then will the whole complex cycle be divided into two simple cycles abgfa and cdegc. The negative quantity Q 3 consists of q, and g/ , given off to the coldest reservoir during the isothermal compressions gf and eg respectively. AVe can now write down the symbolical MEVBRSIBLE CYCLES IN GASES Aflh VAPORS. 45 statement- of the second law for each one of these two simple cycles, viz. : Mr + -fr = f or cycle abcgfa ; ■*■ 1 ■* 3 Adding these two we obtain or, since q, + y,' = Q„ t, "*" y. "*" r. In the same manner we can prove this relation for a com- plex cycle divisible into any number of simple cycles and obtain -^ + -| + -|+...+-^ = 0, or ||=0. If the cycle be of infinite complexity, that is to say, if it be representable by an infinite number of infinitely small elements of adiabatic and isothermal curves, it is evident that the relation ~2~f, —- will still hold true. Of course each one of 46 THERMODYNAMICS OF the Q's will be infinitely small and the sum will -be an in- finite sum. We can therefore express this relation in the notation of the infinitesimal calculus, thus : f f = o. A reversible cycle of this complexity will evidently in the limit be representable by a continuous closed curve. The area bounded by this curve will represent the external work done during the cycle if the cycle be performed in the direct sense, otherwise it will represent the external work spent in order to transfer a certain amount of heat to the hot reservoir, a part of which comes from the cold reservoir. The statement of the second law of thermodynamics (appli- cable to reversible cycles) as given by the last equation, though very general, gives us but little information about the various elements of which the cycle is composed. It gives us no in- formation about the progress of the various physical processes which taken together constitute the cycle. It has the defect which is common to all integral laws. For such laws give us the total effect of a series of physical processes without giving us the separate effect of each process of the series. Take for instance the integral laws of Keppler which describe the motion of the planets around the sun. They tell us all about the areas traced out by radii vectores of the planets during a finite time, about the periodic times, and about the orbits of the planets, but they do not tell us anything about the action which is going on at any and every moment between the sun REVERSIBLE CYCLES IN GASES AND VAPORS. 47 and the planets to produce these integral effects. It took no less a genius than that of a Newton to infer these differential effects from the integral effects discovered by Keppler. The inference was the law of gravitation. To draw that inference Newton had to invent the infinitesimal calculus. We may well assert that he had to invent it ; for a simple consideration will convince you that the process of passing from an integral physical law to the differential law — that is, the law which de- scribes a physical process as it progresses from point to point through infinitely small intervals of space and time — is exactly the same as the mathematical process of passing from an in- tegral to the differential of that integral. We are now ready to discuss the differential of the integral / dQ T = 0. Consider any one of the infinitely small terms -—^ in the Pig. 6. infinite series / -^. The subscripts 12 (Fig. 6) aenote that dQ„ is the heat taken up during the infinitely small element 48 THERMODYNAMICS OF 12 of the cycle and that T lt was the mean temperature of the substance operated upon at that particular moment. It is evi- dent that dQ^ depends on the instantaneous state of' the sub- stance operated upon at that moment, and also upon the nature of the operation represented by the element 12. In other words, dQ„ depends on the volume, pressure, and tem- perature, and the method of their variation during the opera- tion represented by the element 12. Now all these things are completely defined by the co-ordinates of the extremities of the element, hence dQ^ is a function of these co-ordinates. The same is true of the infinitely small quantity -pfr 2 - 12 Consider now a quantity ; 04 - 0= = 40; 0» — 0n-l = 4-i0; 0, — 0n = 40- It is evident that for every cyclic diagram A x + 40 + • • • + 40 = 0. REVERSIBLE CYCLES IN OASES AND VAPORS. 49 When the points 1, 2, 3, ... n are infinitely near each other, then A x , etc., are infinitely small quantities or what we call in calculus the complete differentials of

= 0. This relation will hold true for every function of pressure, volume, and temperature which has definite values at every point of the cyclic diagram and varies continuously from point to point of the diagram. There are evidently an in- finite number of such functions. If that integral is extended not all around the cyclic dia- gram, but only between two points, say points 1 and a, then we shall have the integral evidently equal to a — x ; that is to say, /: d A and / d

= — (

+ I dtp= I d- M0=(0i,-0j)-(0 fl -0j=O, «/(ii)l i/(BA) i/(iB), W (ABh as it should be, since / d

-QT\ P dm) dmVdTJ ~ dT dm' Remembering now that v = um -\- Mcr, hence — = u, we obtain finally dm ff-(#-e) = *f§, (I) This is the statement of the first law of thermodynamics for saturated vapors at which we were aiming continually during our tedious mathematical transformations. Now in what respect is this statement superior to the general statement dQ = dU + pdv? Evidently in this: it con- tains nothing but physical constants of the liquid aud its saturated vapor, most of which, as we shall presently see, are capable of exact experimental measurement. A very famous scientist said once that a department of human knowledge becomes an exact science when it can express its laws in terms of things which are capable of exact experimental measurement. The intrinsic energy U, to be sure, is a thing which we can and did express in terms of a definite unit, the kilogramme-meter; we can also give a perfectly satisfactory definition for it. We can evidently define it in two ways, 66 THERMODYNAMICS OF which we may call the absolute and the relative method of definition. The absolute definition describes U as the energy which we can obtain from the body by a series of processes which would reduce the body to a state in which its intrinsic energy is zero. The relative definition describes U as the energy which we can obtain from a body by a series of pro- cesses which will reduce the body to a state which we call the normal state; and we can select any state for our normal state. For instance, we can define the intrinsic energy of a kilogramme of saturated water-vapor at any temperature as the energy which we can obtain from it by reducing it to a kilogramme of water at 0° C. and a pressure equal to the tension of its saturated vapor at that temperature. Still, when it comes to exact experimental measurement it is not TJ that we measure but the physical constants p, H, 0, and u, and from the measurements of these the relative value of TJ can then in a very limited number of cases be obtained by calculation. Hence the desirability of stating the first law of thermodynamics of saturated vapors in terms of these physi- cal constants which are capable of exact experimental meas- urement instead of in terms of TJ, a quantity which is not capable of direct experimental measurement. It is clear now that the ultimate object of all our long mathematical operations was to rid ourselves by a process of elimination of the quantity TJ. We proceed now to perform the same process of elimina- tion on the general statement of the second law. Carrying out the differentiations indicated in dQ = TdS REVERSIBLE CYCLES IN OASES AND VAPORS. 67 and remembering that T and m are our independent variables, we obtain &*+*&'=*&"+*&'■ This is an identical equation in cZTand dm, and therefore the following relations will hold true : 8© _ T dS_ ~dT dT' dm dm' Comparing these two relations with those obtained by the definitional processes (A) and (B) we obtain r|^ = m(H - G) + MO, T— - o Differentiating now the first equation with respect to m and the second with respect to T and then subtracting the first from the second in order to eliminate 8, we obtain dS dp ,tt p\ dm-dT~ {H ~ C) - 68 THERMODYNAMICS OF But since dm dm ' ' we obtain |=|£-(fl-0 (II) This is our final statement of the second law of thermo- dynamics for reversible processes in saturated vapors. It contains, just like the statement (I) of the first law, a mathe- matical relation between the experimentally measurable physical constants of the liquid and its saturated vapor. By combining (I) and (II) we obtain another very impor- tant relation between these constants, viz., <=Tu^ (Ill) Observation. — It is well to call your attention here to a remark which was made in connection with our deduction of the differential statement of the second law, dQ = TdS, from the integral statement S" REVERSIBLE CYCLES IF GASES AND VAPORS. by The remark was to the effect that the integral statement described the total effect of a series of processes which taken together constitute a reversible cycle, without telling us anything about the separate effects of each particular process of that series. The differential statement, on the other hand, describes completely every minute step in the progress of the reversible cycle. The relations (II) and (III) illus- trate the truth of this remark very forcibly; for they tell us that during every interval of time, no matter how small, the reversible operations will progress in such a way as to main- tain those relations between the physical constants and the variable co-ordinates of the liquid and its vapor which are given by (II) and (III). But do not forget that relation (II) and to same extent relation (III) also is only another way of stating the differential form of the second law, dQ = TdS. More than this. The integral statement limits us to the study of those cycles which are composed of reversible opera- tions only. The differential statement enables us to break through these limits and study cycles consisting of operations some of which are not reversible. For it is evident that we can apply (II) and (III) to every reversible operation of the cycle, and the irreversible operations we can attack by the first law or in any other way that we may consider cor- rect and convenient. This has a very important technical significance, for we shall presently see that the cyclic opera- tions in those types of steam and other caloric engines which prevail to-day are by no means reversible in all their parts. 70 THERMODYNAMICS OF Since numerical values of the physical constants p, H, and C have been tabulated by various experimentalists in terms of the kg. calorie and not the kg. meter as the unit, it is advisable to substitute in our equations (I), (II), and (III) the numerical values of p, H, and C'in terms of the kg. calorie as unit. Let r = the numerical value of p when the unit is a kg. calorie, c — " " h= " " then P_ 0_ H_ J~ r ' J -°' J - n > hence we obtain from (I), (II), and (III) by these substitu- tions dT + c l- JdT , . . . . (I) tt " a a tt a tt a tt " H it tt tt a u tt g r + c-h=J r , (II-) These three equations are our fundamental equations in the thermodynamics of reversible processes in saturated vapors. We now proceed to the next part of our programme, and REVERSIBLE CYCLES IN OASES AND VAPORS. 71 that is the numerical calculation of the physical constants of saturated vapors. Numeral Calculation op the Physical Constants of Saturatfed Vapors. Our three fundamental equations (P), (IP), and (IIP) repre- sent two independent relations [since (III a ) has been deduced from (P), that is the first law, and (IP), that is the second law of thermodynamics] between five unknown quantities, dp viz., r, h, u, c, and — £-. Hence they enable us to calculate ol any two of these quantities when the remaining three are known. That is to say, three of these physical constants of saturated vapors must be determined experimentally and the other two can then be calculated by means of the fundamental laws of thermodynamics. What is meant by experimental determination is simply this: It must be found by experi- mental investigation in what way these physical constants depend on the variable co-ordinates of the body. In our dis- cussion of the general physical properties of saturated vapors we saw that all the physical constants of such a vapor depend on the temperature only, hence the object of an experimental investigation will be to express these physical constants as functions of the temperature T. Three of the above con- stants having been experimentally determined, the remaining two can then be also expressed as functions of the temperature by simple calculation, starting with our fundamental equa- tions (I 3 ), (IP), and (IIP). In most cases r, c, and p have been determined experiment- 72 THERMODYNAMICS OF ally, so that it is generally h and u, that is, the specific heat and the specific volume of saturated vapors, that we have to calculate. We now proceed to carry out these calculations for a par- ticular vapor, and select water vapor for reasons given above. Regnault in his classical researches (Relation des experiences, Mem. de l'Acad. t. xxi, 1847, etc.) made the quantities c, r, and p, that is, the specific heat of water, the heat of evapora- tion, and the tension of saturated vapor of water, the subject of very careful experimental investigations. His results have been verified by all investigators in that field of physical re- search. We shall, therefore, use the values obtained from the results of his investigations. The specific heat of water is expressed, according to Regnault's experimental data, by the following formula : C-1+ .00004* + .0000009*% where t is the temperature in degrees centigrade above the freezing point. For the heat of evaporation experimental data furnish the following relation : r = 606.5 + .305* - / cdt. Substituting the value of c and carrying out the integration, we obtain r = 606.5 - .695* - .00002* 2 - .0000003* 3 . REVERSIBLE CYCLES IN GASES AND VAPORS. 73 For this long formula, Olausius (Mechanische Warmetheorie, vol. i. p. 137) substitutes the following: r = 607 - .708*. To show the agreement between the values of r obtained from these two formulae the following table is given for com- parison : t 0° 50° 100° 150° 200° 606.5 607 571.6 571.6 536.5 536.2 500.7 500.8 464.3 465.4 The agreement is excellent. We shall, therefore, employ Clausius' simpler expression. Taking the experimental data of Regnault's researches, Clausius* constructed the following table for the tension^ of saturated water- vapor at various temperatures : t in C. ° by p in mm. t in C. ° by p in mm. Air Therm. of Hg. Air Therm. of Hg. -20 .91 110 1073.7 -10 2.08 120 1489 4.60 130 2029 10 9.16 140 2713 20 17.39 150 3572 30 31.55 160 4647 40 54.91 170 5960 50 91.98 180 7545 60 148.79 190 9428 70 233.09 200 11660 80 354.64 210 14308 90 525 45 220 17390 100 760 230 20915 * Mechanische Warmetheorie, vol. i. p. 149. 74 THERMODYNAMICS OF Observation 1. To transform p from pressure in mm. Hg to pressure in kg. per sq. m. we simply remember that 760 mm. barometric pressure is equivalent to 10,333 kg. per square meter. If we now wish to know how many kg. per sq. m. correspond to, say, 11,660 mm. barometric pressure, we simply put down the proportion p: 10,333 :: 11,660:760, where p is the pressure in kg. per sq. m., corresponding to 11,660 mm. barometric pressure. 10333X1166 1KQ „ nl p = — = 158,530 kg. per sq. m. (about 229 pounds per square inch). This, then, is the pressure of saturated water-vapor at 200° C. Observation 2. If we refer the tension p and the tem- perature t of the above table to a set of rectangular axes, measuring off t as the abscissae and the corresponding p's as the ordinates, we obtain the curve as in diagram on opposite page. The value of the differential coefficient -—■ (which is evi- dt \ dently the same as -p^\ at any temperature represents the tangent of the angle which the tangent line to the curve at the point corresponding to that temperature makes with the axis of t. An inspection of the curve shows that this angle remains practically constant for considerable intervals of temperature, certainly for intervals of 10°. REVERSIBLE CYCLES IN GASES AND VAPORS. 75 800 p. 4 > 1 / / / , ^ I 500 - 1 J I / / / / . ""i V .JL. %- - - 15 30 45 60 75 90 Consider now any interval of 10° and let dp _ tit 105 a for that interval. ldp d ,, . a . ,, .'• y21~di ' %P> = v same lnterval - 76 THERMODYNAMICS OF This relation enables us to calculate in a very simple manner the quantity — — for any temperature. This is a quantity P (it which we shall need presently. Suppose we wish to calculate (— -jt) , that is, the value of --=(■ for the temperature of \p at Jus p dt r t = 25°. We select, therefore, that 10° interval the mean temperature of which is 25°, that is, the interval between 20° and 30°. We obtain logp so - logp 10 = a j d lj The mean value of p within the limits of integration is very nearly the value of p at 25°, that is,^ 26 . ••• l°g.Pso - log P™ = £- ( dt = ~. But " = (!b L( C !P) - ] °SP™ - Io £A. _ Log P, - Log,,, " p n \dt)» 10 M10 "' where Log stands for Briggs' logarithm, and M is the modulus of that system. We are ready now to take up the calculation of the re- maining physical constants, that is, to find the values of the REVERSIBLE CYCLES IN GASES AND VAPORS. 77 specific heat aud the specific volume of saturated water-vapor for various temperatures within those limits within which the other physical constants were studied experimentally. 1. Calculation of h. From the second law we obtain dr j, _ v , dr , r h = ^ + c -: dt ' rf + 273 Regnault's experiments gave us r = 606.5 + .305£ - / cdt. S' 5 = .305 -& dt Therefore dr ^ + , = .305. 78 THERMODYNAMICS OF In the last term of the expression for h we shall substitute for r the simple expression given by Clausius and obtain h = .305 - 607 -.7 08* 273 + * " The following table contains the calculated values of h for several temperatures : t 0° 50° 100° 150° 200° h - 1.916 - 1.465 - 1.133 -.879 -.676 The physical meaning of this negative specific heat will be considered further on in connection with adiabatic expansion of saturated water-vapor. We pass on to the calculation of the specific volume of saturated water-vapor. 2. Calculation of the Specific Volume of Saturated Water-vapor. The first question to consider is, whether in its saturated state water- vapor follows the law of Mariotte-Gay-Lussac, and if it does not, to what extent and in what way deviations occur. Making use of the fundamental relation (III"'), we find, after replacing (s — a) for u, r _ T(s-a )dp J di REVERSIBLE CYCLES IN OASES AND VAPORS. 79 or 273r_ _ 273p(s - a) ,ldp p dt r ldp /(273 + 0" If the Mariotte-Gay-Lussac law were applicable to satu- rated water - vapor, then from ^ — const, we should have ps X 273 jp3+T) = const ' Since s differs but little from (s — 2 73 + f ( in C,° by Air Thermometer. Calculated from Regnault's data. Calculated from Clausius' formula. 5 30.93 30.46 15 30.60 30.38 25 30.40 30.30 35 30.23 30.20 45 30.10 30.10 55 29.98 30.00 G5 29.88 29.88 75 29.76 29.76 85 29.65 29.63 95 29.49 29.48 105 29.47 29.33 115 29.16 29.17 125 28.89 28.99 135 28.88 28.80 145 28.65 28.60 155 28.16 28.38 165 28.02 28.14 175 27.84 27.89 185 27.76 27.62 195 27.45 27.33 205 26.89 27.02 215 26.56 26.68 225 26.64 26.32 REVERSIBLE CYCLES IN CASES AND VAPORS. 81 The figures given in the column headed " Calculated from Clausius' formula" will be explained presently. We can easily see from this table that the Mariotte-Gay- 1 273 Lussac law does not hold true; for -jp(s — u) dimin- ishes steadily with the increase of temperatures; evidently because the specific volume of saturated steam diminishes more rapidly than the pressure increases with increase of temperature. Clausius found that this formula could be reduced to the more simple one, viz., 1 , . 273 , where m = 31.549, n= 1.0486, a = .007138. By means of this formula Clausius calculated the figures given in the column headed " Calculated from Clausius' for- mula." After this brief digression we return to the calculation of the Specific Volume of Saturated Steam. We had 1 . , 273 , 82 THERMODYNAMICS OF Since we commit an error of a small fraction only of one per cent by neglecting cr in comparison with s, we may write J, ,,273 + 1 Let v' = volume of a kilogr. of air at a pressure p and temperature t, then will ^ = ^'(273 + 0; For a given temperature t, say the freezing temperature, this ratio can be determined experimentally, as will be ex- plained presently. Denoting the ratio -, at the freezing temperature by (-) we shall have (?) = F< m " W >2T3 ; s _fs\m — ne at ' ' v' \W m — n The value of f — ,] can be obtained easily by the following method ; REVERSIBLE CYCLES IN GASES AND VAPORS. 83 Experiment tells us that saturated water-vapor at low tem- peratures obeys the Mariotte-Gay-Lussac law so nearly that we may use the law in practical calculations without commit- ting an appreciable error. On that hypothesis the density of steam at 0° C. is easily obtained. 2 cub. m. H at 0° 0. at a given pressure weigh 2 X .06926 as much as 1 cub. m. of air at the same temperature and pressure; 1 cub. m. at 0° C. at a given pressure weighs 1 X 1.1056 as much as 1 cub. m. of air at the same temperature and pressure; At low temperature, 2 cub. m. H and 1 cub. m. O unite into 2 cub. m. saturated water-vapor (very nearly). .•. 2 cub. m. H„0 at 0° C. at a given pressure weigh 2 X .06926 + 1.1056 as much as 1 cub. m. of air at the same temperature and pressure ; 1 cub. m. of H Q at 0° C. at a given pressure weighs 2 X .06926 + 1.1056 . - as much as 1 cub. m. of air at the & same temperature and pressure. - (*).= 1 1 i(2 X .06926 + 1.1056) _ .622' Therefore s i. m — ne at v' .622 m — n' 84 ThaRMODTNAMICS OF which can also be expressed by a more convenient formula given by Clausius, thus : -, = M- NBK v In this formula M= 1.663, W- .05527, /3 = 1.007164. This formula was used by Clausius to calculate the specific volume of saturated water-vapor at various temperatures. The results are given in the table on page 85. Parallel with these figures are given the figures obtained experimentally by two English engineers, Fairbairn and Tate.* It must be observed that for every temperature we must 'mow first the pressure of saturated vapor at that tempera- ture, and, inserting that pressure in pv' = RT, calculate v'. Observe the close agreement between experiment and theory as worked out by Clausius ; observe also the enormous increase of the density of steam with rising temperature. There is a temperature at which the density of steam is the same as that of water at the same temperature. This is called the critical temperature of water. Above the critical temperature the vapor cannot be liquefied by pressure alone. It is highly probable that all bodies have a critical tem- perature. In the case of the so-called perfect gases the criti- * Transactions of the Royal Society of London, 1860, vol. 150, p. 185, REVERSIBLE CYCLES IN OASES AND VAPORS. 85 Table of Specific Volume of Saturated Water-vapors. t in C.° From Faiibairn and Tate's Clausius' Form. Experimental Table. 58.21 8.23 8.27 68.52 5.29 5.33 70.76 4.83 4.91 77.18 3.74 3.72 77.49 3.69 3.71 79.40 3.43 3.43 83.50 2.94 3.05 86.83 2.60 2.62 92.66 2.11 2.15 117.17 0.947 0.941 118.23 0.917 0.906 118.46 0.911 0.891 124.17 0.769 0.758 128.41 0.681 0.648 130.67 0.639 0.634 131.78 0.619 0.604 134.87 0.569 0.583 137.46 0.530 0.514 139.21 0.505 0.496 141.81 0.472 0.457 142.36 0.465 0.448 144.74 0.437 0.432 cal temperature is very low; hence the necessity of cooling in the liquefaction of gases.* We now come to the last and most important part of our discussion of the application of the two laws of thermo- dynamics to the study of reversible processes in saturated vapors in general and water-vapor in particular, that is, to the discussion of adiabatic and isothermal expansion of satu- rated vapors. * See the researches of Avenarius in Poggendorf 's Annalen, 1874. 86 THERMODYNAMICS OF Abiabatic Expansion of Saturated Water-vapok. We commence with the deduction from our fundamental relations of a mathematical expression which simplifies con- siderably our discussion of adiabatic expansion. By the definitional processes (A) and (B) we obtained ^ = p- dm P > .\dQ = ^dT+ p^dm = \m(H - 0) + MC}dT + pdm. J. 0i7l From the second law (Fundamental Belation II) we obtain 7T-r- dp -P Substituting this value of (H — 0) in the last equation, we derive the relation dQ = ] m(|§, - f) + MO } dT + pdm. Considering now that p, the heat of evaporation, depends on temperature only, it is evident that ^{lT=dp; REVERSIBLE CYCLES IN GASES AND VAPORS. 87 .'• m— mdT-}- pdm — mdp -f pdm = dimp) ; 01 .'. dQ = d(mp) + (MO - n ^)dT, or dQ = Td(^\ + MCdT. This is the expression which we started out to deduce. Iu adiabatic expansion dQ — 0, hence or TdiEj(\ + MCdT = 0, Td(^j + McdT = 0j r fcdT mr m l r l _ M / cdT ~~T~~T~ ~ ~ '' Calculation is simplified very much and the error com- mitted is very small if we put c = constant, during the expan- sion, provided that the expansion does not extend over a very large interval of temperature. In practice this never occurs. mr m,r, , ,_ , T 1 •'• ~ji - -jr- = +Mc log y 5 , or m T ( m t r x , , , , T, 1 88 THERMODYNAMICS OF (a) Condensation during Adidbatic Expansion of Saturated Water-vapor. A very interesting but, from an economical standpoint, a very objectionable phenomenon takes place when satu- rated water-vapor expands adiabatically. Owing to the fact that during such an expansion the temperature (in con- sequence of external work done by the expansion) sinks more rapidly than the density diminishes, the vapor condenses. Hence in order to prevent this condensation it would be necessary to supply heat during the expansion. This, then, is the physical meaning of the negative specific heat, as found above, of saturated water-vapor. During adiabatic compres- sion the vapor would, of course, become superheated. The last equation enables us to calculate the amount of this con- deusation. For example, suppose that m, kilogrammes of saturated water-vapor at initial temperature T x are enclosed in a cylinder by a piston which can glide up and down with- out friction. Let there be no liquid mass in the cylinder. Hence M = m l5 and as the piston goes up slowly owing to the gradual diminution of the pressure, we shall have at any mo- ment in m. = *&+'**%)' Starting with initial temperature T l = 150° -f 273, Clausius* calculated the ratio of the vapor weight in at various tem- peratures T to the initial weight »?,. The following table contains the interesting results of this calculation : * JMechanisclie Warmetheorie, vol. i. p. 164. REVERSIBLE CYCLES IN OASES AND VAPORS. 89 t 150° 1S5« 100° 75° 50° 25° m 1 .956 .911 .866 .821 .776 The amount of condensation is, therefore, very consider- able. This phenomenon contributes to what is known in steam- engineering under the name of cylinder condensation, a pro- cess which, as is easily seen, pulls down the output of the steam-engine. Other and probably quite as serious causes con-tribute to this objectionable process in the cylinder of a steam-engine. Various devices have been suggested and tried in order to overcome this evil, but the discussion of these is outside of the limits of this course. (/?) Calculation of the External Work done during an Adiabatic Expansion. W- - I pdv. dp But v = mu -f- Ma. .'. pdv =pd(mu) — d{mup) — mu^^dT. From our fundamental equation (III) we have Tu mp ,'. pdv = d(mup) qrdT. 90 THERMODYNAMICS OF Since v changes adiabatically, we can make use of the re- lation deduced in the last paragraph when we considered the process of condensation during adiabatic expansion. The re- lation is Td(^-)+MCdT=0, or ^-dT - d{mp) = MCdT. .'. pdv = d{mup) — d(mp) — MCdT. d{mup) - / d(mp) - MO j dT = mup — m i u i p 1 — [mp — ?«,pj + MQ{T y — T). Since the quantities p and C are given, by the experimental formulae discussed above, in kg.-calories, it is preferable to ex- press PFthus: W = mup — m l u 1 p l — J{(mr — m^,) — Mc(T, — T)}. This formula enables us to calculate the external work W in kg.-meters when a certain initial quantity m 1 of saturated water-vapor at temperature T 1 , being in contact witli a quan- tity M — m l of its own liquid at the same temperature, ex- pands adiabatically until its temperature has gone down to a temperature T. Thus: REVERSIBLE CYCLES IN GASES AND VAPORS. 91 Since T t and T are given, p l and p can be found by a refer- ence to Kegnault's table of vapor tensions. Since to, and M are also given, JMc{T x — T) and Jm^r x can be easily calcu- lated. There still remain mr and mu to be calculated. The quantity mr we have already calculated in the preceding paragraph and found mr = r$P-**f> The quantity mu can be easily found thus : From the fundamental relation (IIP) we have T dp mr = w T -—. J dT Substituting this value of mr in the last equation, we ob- tain J f m l r 1 dp\ T, dT ■mu - , {-,:',' ■ Mc log -pY The quantity -^, is the tangent of the angle which the tangent line to the curve of vapor tension, given above, at the point corresponding to temperature T = 273 + t, makes with the axis of t, and can be easily found either graphically or by calculation, thus : Suppose we wish to calculate -?-=, for the temperature 92 THERMODYNAMICS OF t = 110°. On account of the gradual ascent of the curve of vapor tension, we have Eef erring now to Eegnault's table we find p lt0 in mm. = 1489 and j9 110 in mm. = 1073.7. Hence, according to the ex- planation given before, in order. to transform these pressures into kg. per square m. we have to divide by 760 and mul- tiply by 10,333. We obtain \dt)J (1489 - 1073.7)^|F = 564 64 It is seen, therefore, that the two laws of thermodynamics in connection with the experimental data on saturated water- vapor enable us to calculate all the quantities which enter into the expression for the external work done by the adia- batic expansion of such a vapor. It should be noticed that this expression is very much different from the corresponding expression obtained for the adiabatic expansion of a perfect gas. This difference would not exist if saturated vapors obeyed the law of Mariotte-Gay- Lussac. The following table is taken from Clansius * ; its verifica- tion is recommended as a very useful exercise. It contains the external work per kg. of saturated vapor when the initial temperature is t = 150° C. and the initial quantity of the liquid part is zero, hence M = ??? v * Mech. "Warmetheorie, vol. i. p. 167. REVERSIBLE CYCLES IN OASES AND VAPORS. 93 t 150° 125° 100° 75° 50° 35° w 11,300 23,200 35,900 49,300 63,700 Thus the external work done by a kg. of saturated water- vapor in expanding adiabatically from initial temperature of t = 150° C. until its temperature has sunk down to 100° C. is 23200 kg. meters. Obs. 1. In evaporating a kg. of water at 150° to a kg. of steam at 150° work must be done against the vapor pressure corresponding to that temperature. This work can be easily found to be 18,700 kg. meters. Obs. 2. In the above calculation Clausius assumed J — 423.55. (y) External Work done during Isothermal Expansion. During isothermal expansion pressure remains constant, since temperature remains constant. The heat supplied is utilized to compensate two distinct processes which, taken together, constitute the operation of isothermal expansion. The two processes are: separation of the vapor from the liquid mass, and overcoming of the external pressure. Ac- cording to our definition of p, that is, the latent heat of evaporation, the total heat necessary to evaporate m kilo- grammes of vapor is mp. That part of this total heat which does the external work is given by W — J pdv. 94 THERMODYNAMICS OF But v = mu + Ma, and in isothermal expansion dv = —- dm — udm. dm Sim ,\ W = I pudm = pum, since p and u remain constant during this expansion We are ready now to take up the discussion of a complete cycle of operations upon water-vapor. THE INDICATOK DIAGEAM OF A SIMPLE CYCLE. "We shall arrange the cycle in such a way that it shall ap- proach as nearly as possible the cycles which occur in actual steam-engines, without introducing the difficult questions concerning the various causes which produce considerable differences between the results obtained by pure theory and the results obtained from the actual operation of the various types of steam-engines. The existence of these differences is no proof of the weakness of the fundamental features of our theory. On the contrary, these very differences prove its strength, for they point out the important fact that some of the changes or phenomena which take place during the cyclic operations of actual steam-engines have not been taken into account in our theoretical calculations. Careful experimental investigations of these ignored phenomena and the study of their bearing upon the performance of the steam-engine, not only mean the gradual extension towards a complete theory REVERSIBLE CYCLES IN OASES AND VAPORS. 95 of the steam-engine, but they also, by widening out that theory, bring us nearer and nearer to a perfect steam-engine. Fig. 9 represents symbolically the essential parts of a modern steam-engine. A is the boiler, maintained at con- stant temperature T, by the action of the heat supplied by fuel. C is the condenser maintained at constant tempera- ture T . To simplify our discussion, we shall suppose that the condenser is maintained at constant temperature by taking away all the heat that may be supplied to it during the cycle which we are considering, and not by injection of cold water. B is the cylinder in which a piston can glide Up and down without friction. We shall suppose that the cylin- der is impermeable to heat. The action of the pump D will be explained presently. We shall now suppose that by special mechanical contrivances we can at any moment connect the 96 THERMODYNAMICS OF cylinder to or disconnect it from either the boiler A or the condenser G. Operation 1. At the beginning of the cycle the piston is at the bottom of the cylinder. Steam is now admitted from the boiler, and when its quantity is m 1 the connection with the boiler is cut off. Suppose that a quantity of the liquid equal to M — m 1 also enters with the steam. The piston goes up until the volume «, in the cylinder is i>, = JMjMj + Mcr. Since the pressure during this operation is constant and equal to p 1 , (the saturated-vapor tension at the initial tem- perature T^), the external work W 1 done during this operation is given by W 1 = p 1 (m 1 u 1 + Ma). The quantity of heat Q^ consumed during this isothermal expansion is m^p^ In order to represent the cycle graphically, refer the press- ures on the piston and the volume in the cylinder to a set of rectangular axes OA and OB, taking the pressures in kg. per sq. m. for ordinates and the corresponding volumes in cub. m. for abseissse (Fig. 10*). *This diagram was taken from an actual steam-engine. Boiler gauge, 165 ; vacuum gauge, 12.75 ; rev. per minute, 76 ; back pressure, 17 lbs. REVERSIBLE CYCLES IN OASES AND VAPORS. 97 The first operation will be represented by the isothermal line ab. The length of ab = Ob' represents the numerical * Fig. 10. value of v 1 =m 1 u i -\- Mcr. The area abb'O is numerically equal to W v Operation 2. Disconnect the cylinder from the boiler, and by gradually diminishing the pressure let the steam expand from this point on adiabatically until its temperature has sunk to T„ the temperature of the condenser. During this operation the steam, as was explained before, not only remains saturated but even condenses rapidly. The adiabatic curve will be somewhat like the curve be. Its exact form can be traced very accurately by theoretical calculation, but since this is a some- what tedious process we shall omit it from our discussion. The external work done during this operation is represented by the area lec'b'. Denoting it by W^ we shall have, as has been shown before, W,=m^p % — m l u l p l — J{(m,r, — m/,) — Mc{T l — T 2 ). }. 96 THEBMODYNAMICS OF Operation 3. Connect the cylinder with the condenser and compress. The initial volume in the cylinder is v, = (171^ + M a). Let the connection with the condenser be maintained until the piston reaches its initial position again. Since the pressure during this operation remains constant and equal to j? a , the work done during this operation will be, denoting it by W t , w* = — P* v , ~ -~A( JM » M » + Ma )' The curve of compression cd is an isothermal ; it is evidently a straight line parallel to OB. The area CO' Od represents numerically the value of W t . This operation completes the cycle as far as the process in the cylinder is concerned. The diagram abed is called the indicator diagram of the cycle. Its area is numerically equal to the external work done during the cyclic process. Let this be W, then W= W,+ W,+ W % - Mc(T, - T,)}] + [-.?,(«,«, + Ma)] = Ma( Pl - Pt ) + JMc{T x - y.) - J{m t r t - wi.r,). REVERSIBLE CYCLES IN GASES AND VAPORS. 99 Corrections for the Work expended upon tlie Pump. The cycle given above is not complete because the state of the boiler and condenser is not the same at the end of the cycle as in the beginning of it. In the first place, the quantity of the water in the condenser is increased and that in the boiler diminished by M kilogrammes. To make the cycle complete it is necessary now to transfer this quantity M from the condenser- to the boiler by the action of the pump. The work of the pump subtracted from W gives us then the avail- able external work of the complete cycle. The work of the pump is easily calculated thus : In order to transfer the quantity M from the condenser to the pump the piston of the pump must go up until it has in- creased the available volume in the cylinder of the pump by Mcr. During the upward stroke of the latter's piston a valve connects the pump to the condenser, and the condenser press- ure p a forces the quantity M into the cylinder. The work of the pressure p t will evidently be W t = p t MP, + m^T, - TJ. Denote the total external work during this cycle by W ' then W'= W x + W % + W s + W t + [P> u A m , - »».)] + [~ ftV, + tn 3 p, + m, C{T a - T,)]. The expressions in the brackets stand for the various W's. This expression reduced, gives W - (m, - m t )p, + W.P,. We can express W in terms of the initial and final tem- perature by the relation deduced in our discussion of the condensation during adiabatic expansion, viz., T mj) t = - 7>, log jj?; T .: (m, - m t )p t = - -^m^. -* i This substituted in the expression for W gives T — T JP = », lPl -!--_\ i REVERSIBLE CYCLES IN GASES AND VAPORS. 107 The efficiency of the cycle is, according to definition, T.-T. E=~ = jp m iPi rp rp The efficiency, therefore, is just the same as that obtained by operating in a reversible manner upon a perfect gas. It is, therefore, higher than the efficiency of the cycles of any other type of steam-engine. But why, then, should the now prevailing types of steam- engines be so widely different from Carnot's type if a devia- tion from this type brings with it a loss of efficiency ? The complete answer to this question will be given in the course on mechanical engineering. Let two suggestions suffice here: first, efficiency is not the only guiding consideration in the construction of steam-engines, or for that matter in the con- struction of any other kind of engines. The question of out- put is a very serious matter too, and in order to increase the output we must very often make some sacrifice in the efficiency. Secondly, the difference between the efficiency of the now prevailing types of steam-engines and that of the ideal type just described is due far more to other things than to the fact that the operations which we discussed above are not perfectly reversible. Consider the losses due to radiation, the action of the conductingc ylinder-walls on the expanding steam, etc., etc. So that the completeness of the reversibility of the operations through which the steam passes in these engines is not quite as important a matter as it might appear at first sight. 108 THERMODYNAMICS OF SUMMAET. 1. Method of Reasoning which led to the General Form of the Second Law of Thermodynamics. After discussing the application of the first law of thermo- dynamics to the study of reversible operations performed upon perfect gases we passed on to a similar discussion for the next simplest class of bodies, that is, saturated vapors. We suggested, however, that it would be advisable to deduce first another general law which, together with the first law, forms the foundation of the science of thermodynamics : we mean the second law. In doing that we followed practically in the steps of the great Carnot. For he had to discover the second law before he was able to pass from the study of the reversible gas-engine to that of the steam-engine. The first and simplest form of the second law was obtained by considering the efficiency of a Carnot engine operating reversibly upon a perfect gas by simple cycles. This form consisted in a mathematical statement which expressed that the efficiency of such cycles depends on the extreme tempera- tures of the cycles, thus : Q _ T X -T % We then introduced the axiom of Clausius and by means of this axiom we showed that the efficiency of a simple reversible cycle is independent of the substance operated upon. Hence it is always Q _ y, - r, REVERSIBLE CYCLES IN GASES AND VAPORS. 109 "We then transformed this relation into the following : qi ~T~ rp V* It was stated that this transformed expression is preferable because it lends itself more readily to generalization. In order to effect this generalization we passed on to the con- sideration of a complex reversible cycle and obtained the rela- tion ~7p ~r rp T/T7 T • • • T ~fn~ — «» or ■■"^ rp v * We finally considered a reversible cycle of infinite com- plexity and obtained / d 4=o, where the integral is to be extended all around the closed curve which represents graphically the reversible cycle of infinite complexity, that is to say, all around the indicator diagram. This is the integral form of the second law for reversible cycles. But inasmuch as the integral laws in general describe resultant effects only of a series of physical processes and throw but very little light upon each process of that series, we 110 THERMODYNAMICS OF proceeded to deduce from the integral law / -=- = a dif- ferential law, that is to say a relation which will hold true during every interval, no matter how small, of the entire time during which the cyclic process is completed. We obtained That is to say, the heat absorbed by a body during any one of the infinite number of infinitely small operations which taken together form the complete reversible cycle is equal to the absolute temperature of the body multiplied by the incre- ment of the entropy of the body. The definition of the entropy being : 1st. Mathematical and complete. It is a finite, continuous, and singly-valued function of the co-ordinates which define the state of the body, that is, of pressure, volume, and temperature, which satisfies the above differential equa- tion for any reversible operation. 2d. Physical meaning. Its variation during an isothermal operation is equal to the heat absorbed or given off, divided by the absolute temperature at which the operation takes place. Its variation is zero during an adiabatic operation. 2. Forms of the Tivo Laws in the case of Reversible Opera- tions on Saturated Vapors. Starting, then, with our two laws of thermodynamics, dQ — dU -\-pdv, dQ = TdS, REVERSIBLE CYCLES IN GASES AND VAPORS. Ill we took up the discussion of saturated vapors, and in this discussion we followed up as much as possible the line of reasoning which we employed in the discussion of reversible processes in perfect gases. 1st. We discussed the most essential physical properties of saturated vapors by consulting carefully the records of physi- cal research. 2d. "We then performed two simple processes for the purpose of defining the physical constants of a saturated vapor. These two processes we called the definitional processes (A) and (B). They gave us the following two definitional relations : ^ = m(H-C) + MG, dm ' These two definitional relations enabled us then to express the two laws of thermodynamics in the case of saturated vapors in a very convenient form, viz., ^L+C-E = u^, (I) |£-+(7-tf=|, (II) and by combining these two we obtained a third very con- venient relation: fi=Tu^- (Ill) 112 THERMODYNAMICS OF By introducing the kg. calorie as the unit of heat (as is gener- ally done in experimental researches) we obtained QT + C - h -jQT' ' • • • (I) §r + c - h = i (IP) _ Tu dp r -~JdT" • • • (III) 3. Application of the Two Laws to the Study of the Physical Constants of Saturated Vapor. We then proceeded to apply these fundamental thermo- dynamical relations to the study of saturated vapors, and in particular to the study of saturated water-vapor. We divided this discussion into three parts. One part related to the dis- cussion of the constants c, li, r, u, and p, especially to the methods of calculating two of them, h and u, when the other three are given by experimental data. The negative value of the specific heat, the increase of density with the temperature, and the deviation of the behavior of saturated water-vapor from the law of Mariotte-Gay-Lussac were discussed with particular emphasis. 4. Application of the Two Laws to the Study of Isothermal and Adiaoatic Expansion of Saturated Water-vapor. Following the method of discussion which we employed in the case of perfect gases we then took up the very important REVERSIBLE CYCLES IN CASES AND VAPORS. 113 part of our work in thermodynamics, that is, adiabatic and isothermal expansion of saturated water-vapor, the condensa- tion which takes place during adiabatic expansion and the superheating which takes place during adiabatic compression were particularly dwelt upon. The external work done dur- ing adiabatic and isothermal operations received our most careful attention. 5. Non-reversible and Reversible Cycles of Operation upon Saturated Water-vapor. We were ready then to take up the question of the theo- retical efficiency of the non-reversible and the reversible types of steam-engines. This question is, from an engineering standpoint, the most important of all questions in thermo- dynamics. It is also exceedingly important from a historical point of view, for the study of this question led Carnot to the discovery of the two laws of thermodynamics. The external work done during each component operation of these cycles was calculated and expressed by f ormulse which admit of being reduced to actual figures, so that the action of each component operation could be studied by finding the numerical value of this action in terms of kg. meters. The theoretical efficiency of non-reversible machines was then shown to be smaller than that of the reversible type, and the efficiency of this was then demonstrated by actual calculation to be the same as that of a Carnot reversible engine operating by simple reversible cycles upon a perfect gas. There remains still another important application of the two laws of thermodynamics which is within the limits of 114 THERMODYNAMICS. this purely theoretical course. It is the application to the study of the flow of gases and vapors. In this part of our discussion we propose to follow closely the beautifully worked out Chapter IX in Peabody's " Thermodynamics of the Steam- engine." These are the most essential elements of theoretical thermo- dynamics, upon which as a strong foundation the practical engineer must raise the vast structure of the beautiful science of Caloric Engineering. SHORT-TITLE CATALOGUE OP THE PUBLICATIONS OP JOHN WILEY & SONS, New York. London: CHAPMAN" & HALL, Limited. 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